The table tells us that the x coordinate. It also tells us that y is always x + 1.
For #1 you plot the coordinate (0, 1).
0 (the x coordinate) is given to us already.
1 (the y coordinate) is needed to be found by the equation.
You would then need to fill in the equation given with the x coorident.
y = 0 + 1
Then, solve for y.
0 + 1 = 1
The y coordinate is 1
Go to the horizontal line (x) and find 0.
Then go to the veridical line (y) and find 1.
Then match up the the x and y to plot the coordinate.
You would continue with this equation with the rest of the xs.
This is a hard concept to explain in just words, so feel free to comment with any more questions. :D
<em>Evaluate 1/4c+3d when c=6, and d=7.</em>
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Replace c with 6, and d with 7:-
On simplification,
On further simplification,
On further simplification,
Adding the numerators,
Finally, Reducing the fraction:-
<h3>Good luck with your studies.</h3>
Answer:
First, we need to set up a (y−k)^2=4p(x−h). After plugging in all of your values, you would get (x-5)^2=-4(y-1). Now, we need to solve in terms of y by dividing each side by the factors that don't contain the variable
Step-by-step explanation:
