Answer:
To get number of neutrons, you must have the mass number and atomic number of that atom.
atomic number is number of protons
Answer:
vertebrate and invertebrates
Explanation:
All Vertebrates have a skeletal structure with a spinal backbone and well developed internal skeleton made up of bones and cartilage while Invertebrates have no backbone.
Vertebrate include fish, amphibians, reptiles, birds and mammals. Invertebrates include worms and jellyfish, spiders and crabs.
<u>common characteristics among vertebrates and invertebrates </u>
○ multi-cellular.
○ heterotrophs (cannot make their own food) and must get their energy by consuming plants or other animals.
○ obtain food and oxygen for energy,
Answer:
Explanation:
idk why all u guys like trump who do.. hes just a big pain in the a*s.
1) Zn + 2 HCl = ZnCl2 + H2 ( <span>single replacement )
2) </span>2 NaCl + F2 = 2 NaF + Cl2 ( <span>single replacement )
3) </span>2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3 ( <span>double replacement )
4) </span>2 K + MgBr2 = 2 KBr + Mg ( <span>single replacement )
Answer 3
hope this helps!</span>
Answer:
pH = 2.03
Explanation:
The pH can be calculated using the following equation:
![pH = -log [H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20)
(1)
The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺
1.00 M
![K_{a} = \frac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}](https://tex.z-dn.net/?f=%20K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BCH_%7B3%7DCOOH%5D%7D%20)
Solving the above equation for H₃O⁺, we have:
![[H_{3}O^{+}] = \frac{Ka*[CH_{3}COOH]}{[CH_{3}COO^{-}]}](https://tex.z-dn.net/?f=%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7BKa%2A%5BCH_%7B3%7DCOOH%5D%7D%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%7D%20)
(2)
The dissociation constant is equal to:
Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:
CH₃COOX ⇄ CH₃COO⁻ + X⁺
5.00x10⁻³ M
![K_{sp} = [CH_{3}COO^{-}][X^{+}]](https://tex.z-dn.net/?f=%20K_%7Bsp%7D%20%3D%20%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%5BX%5E%7B%2B%7D%5D%20)
![[CH_{3}COO^{-}] = \frac{K_{sp}}{[X^{+}]} = \frac{9.40 \cdot 10^{-6}}{5.00 \cdot 10^{-3}} = 1.88 \cdot 10^{-3} M](https://tex.z-dn.net/?f=%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%20%3D%20%5Cfrac%7BK_%7Bsp%7D%7D%7B%5BX%5E%7B%2B%7D%5D%7D%20%3D%20%5Cfrac%7B9.40%20%5Ccdot%2010%5E%7B-6%7D%7D%7B5.00%20%5Ccdot%2010%5E%7B-3%7D%7D%20%3D%201.88%20%5Ccdot%2010%5E%7B-3%7D%20M)
By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:
![[H_{3}O^{+}] = \frac{1.74 \cdot 10^{-5}*[1.00]}{[1.88 \cdot 10^{-3}]} = 9.26 \cdot 10^{-3} M](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B1.74%20%5Ccdot%2010%5E%7B-5%7D%2A%5B1.00%5D%7D%7B%5B1.88%20%5Ccdot%2010%5E%7B-3%7D%5D%7D%20%3D%209.26%20%5Ccdot%2010%5E%7B-3%7D%20M)
Hence, the pH is:
![pH = -log [H_{3}O^{+}] = -log [9.26 \cdot 10^{-3}] = 2.03](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20-log%20%5B9.26%20%5Ccdot%2010%5E%7B-3%7D%5D%20%3D%202.03%20)
Therefore, the pH must be 2.03 to yield a solution in which the concentration of X⁺ is 5.00x10⁻³M.
I hope it helps you!
