Answer:
The equilibrium constant of the given reaction is 0.01351.
Explanation:

The equilibrium constant of the reaction = 
...[1]

The equilibrium constant of the reaction = 
..[2]
![[Cl^-]=\frac{K_4\times [AgCl]}{[Ag^+]}](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D%5Cfrac%7BK_4%5Ctimes%20%5BAgCl%5D%7D%7B%5BAg%5E%2B%5D%7D)

The expression of equilibrium constant of the creation is ;
![K=\frac{[AgCl]^2[Pb^{2}]}{[PbCl_2]][Ag^+]^2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BAgCl%5D%5E2%5BPb%5E%7B2%7D%5D%7D%7B%5BPbCl_2%5D%5D%5BAg%5E%2B%5D%5E2%7D)
Dividing [1] by [2]
![\frac{K_3}{K_4}=\frac{\frac{[Pb^{2+}][Cl^-]^2}{[PbCl_2]}}{\frac{[Ag^+][Cl^-]}{[AgCl]}}](https://tex.z-dn.net/?f=%5Cfrac%7BK_3%7D%7BK_4%7D%3D%5Cfrac%7B%5Cfrac%7B%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5E2%7D%7B%5BPbCl_2%5D%7D%7D%7B%5Cfrac%7B%5BAg%5E%2B%5D%5BCl%5E-%5D%7D%7B%5BAgCl%5D%7D%7D)
![\frac{K_3}{K_4}=\frac{[Pb^{2+}][Cl^-][AgCl]}{[PbCl_2][Ag^+]}](https://tex.z-dn.net/?f=%5Cfrac%7BK_3%7D%7BK_4%7D%3D%5Cfrac%7B%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5BAgCl%5D%7D%7B%5BPbCl_2%5D%5BAg%5E%2B%5D%7D)
Substituting the value of
from [2] :
![\frac{K_3}{K_4}=\frac{[Pb^{2+}][AgCl]}{[PbCl_2][Ag^+]}\times \frac{K_4\times [AgCl]}{[Ag^+]}](https://tex.z-dn.net/?f=%5Cfrac%7BK_3%7D%7BK_4%7D%3D%5Cfrac%7B%5BPb%5E%7B2%2B%7D%5D%5BAgCl%5D%7D%7B%5BPbCl_2%5D%5BAg%5E%2B%5D%7D%5Ctimes%20%5Cfrac%7BK_4%5Ctimes%20%5BAgCl%5D%7D%7B%5BAg%5E%2B%5D%7D)



The equilibrium constant of the given reaction is 0.01351.
Name:<span> Polonium </span>
Symbol:<span> Po </span>
Atomic Number:<span> 84 </span>
Atomic Mass:<span> (209.0) amu </span>
Melting Point:<span> 254.0 °C (527.15 K, 489.2 °F) </span>
Boiling Point:<span> 962.0 °C (1235.15 K, 1763.6 °F) </span>
Number of Protons/Electrons:<span> 84 </span>
Number of Neutrons:<span> 125 </span>
Classification: Metalloid
Crystal Structure:<span> Monoclinic </span>
Density @ 293 K:<span> 9.4 g/cm</span>3
Color:<span> Unknown</span>
Atomic Structure<span> <span>
Number of Energy Levels: 6<span>
First Energy Level: 2
Second Energy Level: 8
Third Energy Level: 18
Fourth Energy Level: 32
Fifth Energy Level: 18
Sixth Energy Level: 6
does it help?</span></span></span>
C.commanding the army the the navy would be right I think
<h3>
Answer:</h3>
2 M
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Unit 0</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Aqueous Solutions</u>
- Molarity = moles of solute / liters of solution
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
36.7 g CaF₂
300 mL H₂O
<u>Step 2: Identify Conversions</u>
Molar Mass of Ca - 40.08 g/mol
Molar Mass of F - 19.00 g/mol
Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol
1000 mL = 1 L
<u>Step 3: Convert</u>
<em>Solute</em>
- Set up:

- Multiply:

<em>Solution</em>
- Set up:

- Multiply:

<u>Step 4: Find Molarity</u>
- Substitute [M]:

- Divide:

<u>Step 5: Check</u>
<em>Follow sig fig rules and round.</em> <em>We are given 1 sig fig as our lowest.</em>
1.56677 M ≈ 2 M