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Natasha2012 [34]
3 years ago
8

How does the number of molecules in 1 mol of oxygen compare with the number of molecules in 1 mol of nitrogen?

Chemistry
1 answer:
frozen [14]3 years ago
7 0

Hey there!

The number of molecules is the same.

One mole of a type of molecule is <u><em>always</em></u> 6.022 x 10²³ molecules, so no matter what the type of molecule is there will be the same amount of molecules.

The mass, volume, or other properties can be different, but the number of molecules will be the same.

Hope this helps!

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We have a sample of water vapor which cools from 150 °C to 125 °C. What happens to the motion of the molecules during this time
pentagon [3]

The motion of the molecules decreases.

<u>Explanation</u>:

  • Gases are formed when the energy in a system overcomes the attractive forces between the molecules. The gases expand to fill the space they occupy. In this way, the gas molecules interact little. In the gaseous state, the molecules move very quickly. As the temperature decreases, the amount of movement of the individual molecules also decreases.
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5 0
3 years ago
. an ionic compound is composed of 34.95 g of iron and 15.05 g of oxygen. find the empirical formula of this compound.
Contact [7]

Empirical formula of ionic compound is FeO. In which the composition of atoms is 1 : 1.

Empirical formula of an ionic compound is defined as the formula which gives whole number ratio of atoms of various elements present in molecule of compund.

mass of iron in compound = 34.95 g

molar mass of iron = 55.8 g

mass of oxygen in compound = 15.05 g

molar mass of oxygen = 32 g

number of moles of iron present in the compound are ratio of mass of iron in compound/ molar mass of iron

number of moles of iron in compound= 34.95 / 55.8 = 0.6263 ~ 1

number of moles oxygen in compound= 15.05/ 32 = 0.473 ~ 0.5

the ratio of the number of oxygen atoms to number of iron atoms present in one formula unit of iron compund is 2×0.5 / 1 = 1 : 1

Hence , the required empirical formula of iron compound is FeO.

To learn more about Emiprical formula, refer:

brainly.com/question/1439914

#SPJ4

3 0
1 year ago
43. A stock glucose standard has a concentration of 1,000 mg/dL. A 1/5 dilution of this standard is made. What would be the fina
Nat2105 [25]

The final concentration of the diluted standard is 0.2 mg/dL.

<h3 /><h3>What is concentration of glucose standard after 1/5 solution?</h3>

Using the dilution formula:

  • C1V1 = C2V2

where

  • C1 is initial concentration
  • V1 initial volume
  • C2 is final concentration
  • V2 is final volume.

Assuming a final volume of 100 mL, and since a 1/5 dilution is made:

C1 = 1.00 mg/dL

V1 = 20

C2 = ?

V2 = 100 mL

C2 = C1V1/V2

C2 = 20 × 1/100

C2 = 0.2 mg/dL

Therefore, the final concentration of the diluted standard is 0.2 mg/dL.

Learn more about dilution at: brainly.com/question/24881505

6 0
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