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2 years ago

Can someone please answer these

Chemistry

1 answer:

Karo-lina-s [1.5K]2 years ago

5 0

Answer:

A particle is a small peice of anything (any kind of material)

a. element

b. compound

c. mixture

d. compound

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How many times do u have to run back and forth across a football field to be meter

Taya2010 [7]

You would have to run 100 kilometers across it once. Then you will have to run 10 meters across it because a football field is 110 meters according to the NFL’s website

7 0

3 years ago

Wat is significant figures

Sav [38]

Answer:

0.052301 km have 5 significant figure
400 cm have 1 significant figure
50.0 m have 3 significant figure
4500.01 ml have 6 significant figure

Explanation:

According to rules of significant figure

0.052301 km have 5 significant figure:

Zero to the left of the first non zero digit not significant.
Zero between the non zero digits are significant.

400 cm have 1 significant figure:

Trailing zeros are not significant in numbers without decimal points.

50.0 m have 3 significant figure:

Trailing zeros are significant in numbers when there is decimal points.

4500.01 ml have 6 significant figure:

Zero between the non zero digits are significant.

4 0

3 years ago

Determine whether each molecule given below is polar or nonpolar. of2

sergejj [24]

Answer : The molecule $OF_2$ is a polar molecule.

Explanation :

Polar molecule : When the arrangement of the molecule is asymmetrical then the molecule is polar.

Non-polar molecule : When the arrangement of the molecule is symmetrical then the molecule is non-polar.

The given molecule is, $OF_2$

The electronegativities of oxygen and fluorine are different. The molecular geometry of $OF_2$ is bent. As, Fluorine is more elctronegative than the oxygen. So, the arrows putting towards the more electronegative element i.e, fluorine. These arrows do not balance each other. Due to this, the asymmetrical arrangement of these bonds makes the molecule polar.

Hence, the given molecule $OF_2$ is polar.

7 0

3 years ago

Question 2 of 50

wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

Write the balanced chemical equation for the given reaction.
Convert the mass of calcium carbonate into moles.
Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

$CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}$

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

$mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}$

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

$mol \ CaO \ = 0.2498 \ mol$

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

$mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g$

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

$\boxed {mass \ CaO \ = 14 \ g}$

Learn More

Learn more about stoichiometry brainly.com/question/12979299
Learn more about mole conversion brainly.com/question/12972204
Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0

3 years ago

Plz hleeeeeeeeeep meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

andrezito [222]

Runoff (Hope this helped)

4 0

2 years ago