3 years ago

I NEED HELP PLZ I WILL GIVE THANKS AND BRAINLIST

Mathematics

2 answers:

alexira [117]3 years ago

6 0

The mapping is not a function

sertanlavr [38]3 years ago

4 0

It’s a function, each number has a different number.

You might be interested in

A rectangle has a length that is 2 inches less than its with. What is the area of the rectangle? Use w as your variable for widt

pogonyaev

Answer:

See explanation.

Step-by-step explanation:

length = w-2

area = w*(w-2)

4 0

2 years ago

What is Sin x = 23/45

BartSMP [9]

Answer:

0.00892045

Step-by-step explanation:

i put your question in a sine calc and thats what it said

5 0

3 years ago

Help me with this this is confusing <br> give me the answer

PSYCHO15rus [73]

what's the question?

8 0

2 years ago

A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rect

gayaneshka [121]

Hello,

It 's difficult to translate that in french.

l=16 ^(1/5)
w=2^(1/5)
Area=32^(1/5)=(2^5)^(1/5)=2 (in²)

7 0

3 years ago

Read 2 more answers

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

3 years ago

Read 2 more answers