The question regards composite functions. A composite function is a function composed of more than one function. Sorry for saying the word function so many times there, it's just what it is...
The phrase f(g(x)) means 'perform g on an input x, then perform f on the result'. You can then see that there are many options for f(x) and g(x) here, in fact an infinite number of one were to be ridiculous about it.
However a sensible choice might be g(x) = x^2, and f(x) = 2/x + 9. Checking:
g(x) = x^2
f(g(x)) = 2/(x^2) + 9
That is the first question dealt with. Next up is Q2. It is relatively simple to show that these functions are inverses. If you start with a value x, apply a function and then apply the function's inverse, you should return to the same starting value x. To take a common example, within a certain domain, sin^-1(sin(x)) = x.
f(g(x)) = (sqrt(3+x))^2 - 3 = 3 + x - 3 = x
g(f(x)) = sqrt(x^2 - 3 + 3) = sqrt(x^2) = x
A final note is that this is only true for a certain domain, that is x <= 0. This is because y = x^2 is a many-to-one function, so unrestricted it does not have an inverse. Take the example to illustrate this:
If x = -2, f(x) = (-2)^2 - 3 = 4 - 3 = 1
Then g(f(x)) =sqrt(1 + 3) = sqrt(4) = 2 (principal value).
However the question isn't testing knowledge of that.
I hope this helps you :)
Answer:
<h2>A. 1/3</h2>
Step-by-step explanation:
Answer:
A. $,143,699,010
Step-by-step explanation:
Use a calculator my friend.
Answer:
- high tide occurs at 12 noon and 12 midnight
- Low tide occurs at 6 a.m and 6 p.m
- maximum depth value = 20 ft
- Minimum depth value = 15 ft
Step-by-step explanation:
The depth is modelled as;
y = 20 + 5 cos (πt/6)
We are told that t = 0 represents 12:00 midnight.
This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.
Max depth value is;
y = 20 + 5(0)
y = 20 ft
Minimum depth value will be the low tide and it will be when the cos function is equal to -1.
Thus;
y = 20 + 5(-1)
y = 15 ft
Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;
12 noon
Also, let's check for low tide.
Let's try t = 6 which means 6 a.m
Thus;
y = 20 + 5 cos (π(6)/6)
y = 20 + 5 cos π
Cos π has a value of -1
Thus;
y = 20 + 5(-1)
y = 20 - 5
y = 15 ft
Thus;
Low tide occurs at 6 a.m and 6 p.m
Answer:
This question is actually a riddle. The answer to this riddle is, "Buoy meets gull."
Step-by-step explanation:
