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Ulleksa [173]
3 years ago
10

HELP ASAP

Mathematics
2 answers:
Tems11 [23]3 years ago
4 0
A cylinder is formed
bezimeni [28]3 years ago
3 0

Answer:

a cylinder.

Step-by-step explanation:

I hope this helps

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One approximate solution to the equation cos x = -0.60 for the domain 0° ≤ x ≤ 360° is
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307 klkammamamamammama
5 0
1 year ago
What is the value of the constant in the equation that relates the height and
VashaNatasha [74]

Answer:

10 over=5

i asked this quetion

7 0
2 years ago
Read 2 more answers
Please Answer <br><br> This is due by tomorrow night and I need help
labwork [276]

Answer:

AY = 16

IY = 9

FG = 30

PA = 24

Step-by-step explanation:

<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>

Let us solve the problem

In Δ AFT

∵ Y is the centroid

∵ AP, TI, and FG are medians

→ By using the rule above

∴ Y divides AP at ratio 1: 2 from the base FT

∴ AY = 2 YP

∵ YP = 8

∴ AY = 2(8)

∴ AY = 16

∵ PA = AY + YP

∴ AP = 16 + 8

∴ AP = 24

∵ Y divides TI at ratio 1: 2 from the base FA

∴ TY = 2 IY

∵ TY = 18

∴ 18 = 2

→ Divide both sides by 2

∴ 9 = IY

∴ IY = 9

∵ Y divides FG at ratio 1:2 from the base AT

∴ FY = 2 YG

∵ FY = 20

∴ 20 = 2 YG

→ Divide both sides by 2

∴ 10 = YG

∴ YG = 10

∵ FG = YG + FY

∴ FG = 10 + 20

∴ FG = 30

5 0
3 years ago
What is the solution to the system of equations?<br><br> 6x – 9y = 16<br><br> 2x – 3y = 7
kifflom [539]
The first step for solving this problem is to multiply both sides of the bottom equation by -3.
\left \{ {{6x-9y=16} \atop {-6x + 9y = -21}} \right.
Add the two equations together.
6x - 9y - 6x + 9y = 16 - 21
Eliminate the opposites.
-9y + 9y = 16 - 21
Remember that the sum of two opposites equals 0,, so the equation becomes the following:
0 = 16 - 21
Calculate the difference on the right side of the equation.
0 = -5
This means that the statement \left \{ {{6x-9y=16} \atop {2x-3y=7}} \right. is false for any value of x and y. That means that the answer to your question is (x,y) ∈ ∅,, or no solution.
Let me know if you have any further questions.
:)
8 0
3 years ago
Solve and state any extraneous solutions
Mice21 [21]

\frac{3x}{x - 1}  + 2 =  \frac{3}{x - 1}

\frac{3x}{x - 1} +  \frac{2(x - 1) }{ x - 1}   =  \frac{3}{x - 1}

\frac{3x}{x - 1}  +  \frac{2x - 2}{ x - 1}  =  \frac{3}{x - 1}

\frac{3x + 2x - 2}{ x - 1}  =  \frac{3}{x - 1}

3x + 2x - 2 = 3

5x - 2 = 3

5x = 3 + 2

5x = 5

x =  \frac{5}{5}

x = 1

3 0
3 years ago
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