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Ulleksa [173]
3 years ago
10

HELP ASAP

Mathematics
2 answers:
Tems11 [23]3 years ago
4 0
A cylinder is formed
bezimeni [28]3 years ago
3 0

Answer:

a cylinder.

Step-by-step explanation:

I hope this helps

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Identify the stem of the following number: 231. <br> A. 1 <br> B. 2 <br> C. 3 <br> D. 23
Kruka [31]
stem = 23
leaf = 1

Answer is choice D

The leaf is always a single digit because you can have multiple leaves without any separating mark. If you have something like "123" on the leaf column, then that means you have three leaves of 1, 2 and 3 which correspond to the same stem.
8 0
3 years ago
In a fruit cocktail, for every 20 ml of orange juice you need 10 ml of apple juice and 15 ml of coconut milk. What proportion of
MariettaO [177]

Answer:

1/3

Step-by-step explanation:

20 ml + 10 ml + 15 ml = 45 ml total

15 ml coconut milk/45 ml total = 15/45 = 1/3 (as a fraction)

7 0
3 years ago
Below are 36 sorted ages of an acting award winner. Find Upper P70 using the method presented in the textbook.
Leona [35]
The upper 70th percentile is the number below which 70% of the data lie.

The 70th percentile position is given by:

P_{70}= \frac{70N}{100} = \frac{70(36)}{100} =25.2

Thus, the 70th percentile position is approximately the 25th data item (after the data has been arranged in acsending order).

Given the following data:
<span>16 24 25 26 27 29 36 39 39 39 40 44 45 47 47 48 50 51 51 53 53 54 57 58
58 60 65 66 67 69 69 71 72 74 74 74

The 25th data in the data set is 58.

Therefore, the upper P70 is 58.
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6 0
3 years ago
Read 2 more answers
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
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The length of each side of the base is 9 inches. only 5 size of the cardboard box has an cardboard because of the sixth side is open
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