2 years ago

PLEASE PLEASE HELP ME

Mathematics

1 answer:

Alexus [3.1K]2 years ago

3 0

Y=-2x-2 it is the only one that is perfectly perpendicular and passes through (-3,4)

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Use the x-intercept method to find all real solutions of the equation.<br> x^3-8x^2+9x+18=0

meriva

Answer:

a. $x=-1,3,\:or\:6$

Step-by-step explanation:

The given equation is;

$x^3-8x^2+9x+18=0$

To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator or software.

The corresponding function is

$f(x)=x^3-8x^2+9x+18$

The solution to $x^3-8x^2+9x+18=0$ is where the graph touches the x-axis.

We can see from the graph that; the x-intercepts are;

(-1,0),(3,0) and (6,0).

Therefore the real solutions are:

$x=-1,3,\:or\:6$

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3 years ago

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Ms. Cebrera counted the number of absences each student in her class had last year.

sergejj [24]

The best answer would be c

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Two faulty machines, M1 and M2, are repeatedly run synchronously in parallel (i.e., both machines execute one run, then both exe

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The event that either M1 or M2 fails has probability

$P(M_1\text{ fails or }M_2\text{ fails})=P(M_1\text{ fails})+P(M_2\text{ fails})-P(M_1\text{ and }M_2\text{ both fail})$

by the addition rule. Failure events are independent, so

$P(M_1\text{ and }M_2\text{ both fail})=P(M_1\text{ fails})P(M_2\text{ fails})$

so that

$P(M_1\text{ fails or }M_2\text{ fails})=p_1+p_2-p_1p_2$

Denote this probability by $p$ . Then $X$ follows a geometric distribution with this parameter $p$ and has density

$P(X=x)=\begin{cases}(1-p)^{x-1}p&\text{for }x\ge1\\0&\text{otherwise}\end{cases}$

The expectation is $\dfrac1p=\dfrac1{p_1+p_2-p_1p_2}$ .

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3 years ago

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victus00 [196]

Answer:

18 cm

Step-by-step explanation:

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2 years ago

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babunello [35]

Answer:

218,205,858,257,659,822,002

Step-by-step explanation:

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3 years ago