PLEASE HELP ASAP!!! CORRECT ANSWERS PLEASE!!!

Mathematics

2 answers:

Afina-wow [57]3 years ago

6 0

See attached picture for the answers

aev [14]3 years ago

6 0

By the traingle sum theorem, the sum of the angles in a triangle is 180°. Therefore, using the given and triangle sum theorem, m(∡P) + m(∡Q) + m(∡R) = 180°.

(5x)° + (5x)° + (8x)° = 180°. Simplifying the equation gets 18x=180°. Finally, using the division property of equality, x=10°.

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If a student receives 86 text messages during this class, how many text messages did he or she receive per minute?

frozen [14]

Answer:

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3 years ago

Simplified product ?

mel-nik [20]

Answer:

Last choice is correct.

Step-by-step explanation:

$\left(\sqrt{10x^4}-x\sqrt{5x^2}\right)\left(2\sqrt{15x^4}+\sqrt{3x^3}\right)$

$\left(x^2\sqrt{10}-x\cdot x\sqrt{5}\right)\left(2\cdot x^2\sqrt{15}+x\sqrt{3x}\right)$

$\left(x^2\sqrt{10}-x^2\sqrt{5}\right)\left(2x^2\sqrt{15}+x\sqrt{3x}\right)$

$x^2\sqrt{10}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)-x^2\sqrt{5}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)$

$2x^4\sqrt{150}+x^3\sqrt{30x}-2\sqrt{75}x^4-x^3\sqrt{15x}$

$2x^4\cdot5\sqrt{6}+x^3\sqrt{30x}-2\cdot5\sqrt{3}x^4-x^3\sqrt{15x}$

$10x^4\sqrt{6}+x^3\sqrt{30x}-10\sqrt{3}x^4-x^3\sqrt{15x}$

$10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$

Hence final answer is $10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$

5 0

3 years ago

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AysviL [449]

Answer:

If two figures have the same size and shape, then they are congruent. so if they have the same shape and size even if they are flipped or mirrored they are congruent.

Step-by-step explanation:

The term congruent is often used to describe figures like this, the pictire below. if you look up congruent shapes and look at many examples that will definitely help you understand alot more better what congruent means.