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3 years ago

Please do not send me p d f s or links

Mathematics

2 answers:

Basile [38]3 years ago

5 0

Answer:

Height of girls:

Range = 11

IQR = 6

Height of boys:

Range = 12

IQR = 4

Step-by-step explanation:

I placed the height of girls from lowest to greatest (49,49,52,53,53), 54, (57,57,58,58,60) then I subtracted 49 from 60. I subtracted 49 from 60 (60 - 49 = 11) because you subtract the smallest number in the data from the highest number to get the range. Now to find the IQR, you need to find the median. The median is the number right in the middle of the data so in this case it's 54. You can make parenthesis for the all the number behind and in front of the median like I did (You don't have to do it, it makes it easier for me to find the Q1 and Q3). You have to find the Q1 and Q3 which is in the middle of the numbers behind and after 54. For our Q1 it's 52 and for our Q3 it's 58. You can think of the Q1 and Q3 as a median or the middle number for the data. Just in case you need it I placed the Height of the boys here. (52, 54, 57, 58, 58,) 59, (59, 61, 61, 63, 64).

olga nikolaevna [1]3 years ago

4 0

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A recent Harris Poll survey of 1010 U.S. adults selected at random showed that 627 consider the occupation of firefighter to hav

Semmy [17]

Answer: 0.62

Step-by-step explanation:

Given : A recent Harris Poll survey of 1010 U.S. adults selected at random showed that 627 consider the occupation of firefighter to have very great prestige.

i.e. The sample size of U.S. adults : n= 1010

The number of U.S. adults consider the occupation of firefighter to have very great prestige : x= 627

Now , the probability that a U.S adult selected at random thinks the occupation of firefighters has very great prestige will be :

$\hat{p}=\dfrac{x}{n}\\\\=\dfrac{627}{1010}=0.620792079208\approx0.62$ [ To the nearest hundredth]

Hence, the estimated probability that a U.S adult selected at random thinks the occupation of firefighters has very great prestige = 0.62

5 0

3 years ago

What is the answer to 4|x-1|=12

STatiana [176]

Answer:

(4,0) and (- 2,0): Answer

Step-by-step explanation:

Absolute value questions have two essential steps.

1. Solve the equation as it is written.

2. Solve it changing the sign of the right hand side. I will include a graph to confirm my answer

4*abs(x - 1) = 12 Divide by 4

abs(x - 1) = 12/4
abs(x - 1) = 3 Equate this to 3
x - 1 = 3 Add 1 to both sides
x - 1 + 1 = 3 + 1 Combine
x = 4

4*abs(x - 1) = - 12 Divide by 4

abs(x - 1) = - 12/4
abs(x - 1) = - 3
x - 1 = - 3 Add 1 to both sides
x - 1 + 1 = -3 + 1
x = - 2

So this has 2 answers

(4,0) and (- 2,0)

5 0

3 years ago

What is the difference in volume, in cubic feet, of the two prism?

Olegator [25]

Answer:

What prisms

Step-by-step explanation:

7 0

3 years ago

Simplify 5 √16 + 12 √54 - 3 √8

USPshnik [31]

20+36. l6-6/2

v. v

decimal form

99.69634936

8 0

2 years ago

The Slow Ball Challenge or The Fast Ball Challenge.

cupoosta [38]

Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

$Pitches = 7$

$P(Hit) = 80\%$

$Win = \$60$

$Lost = \$10$

Fast Ball Challenge

$Pitches = 3$

$P(Hit) = 70\%$

$Win = \$60$

$Lost = \$10$

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 7$ --- pitches

$x = 7$ --- all hits

$p = 80\% = 0.80$ --- probability of hit

So, we have:

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

$P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}$

$P(7) =1 * 0.80^7 * (1 - 0.80)^0$

$P(7) =1 * 0.80^7 * 0.20^0$

Using a calculator:

$P(7) =0.2097152$ --- This is the probability that he wins

i.e.

$P(Win) =0.2097152$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 -0.2097152$

$P(Lose) = 0.7902848$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.2097152 * \$60 + 0.7902848 * \$10$

Using a calculator, we have:

$Expected = \$20.48576$

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 3$ --- pitches

$x = 3$ --- all hits

$p = 70\% = 0.70$ --- probability of hit

So, we have:

$P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}$

$P(3) =1 * 0.70^3 * (1 - 0.70)^0$

$P(3) =1 * 0.70^3 * 0.30^0$

Using a calculator:

$P(3) =0.343$ --- This is the probability that he wins

i.e.

$P(Win) =0.343$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 - 0.343$

$P(Lose) = 0.657$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.343 * \$60 + 0.657 * \$10$

Using a calculator, we have:

$Expected = \$27.15$

So, we have:

$Expected = \$20.48576$ -- Slow ball

$Expected = \$27.15$ --- Fast ball

<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>

5 0

3 years ago