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3 years ago

Please do not send me p d f s or links

Mathematics

2 answers:

Basile [38]3 years ago

5 0

Answer:

Height of girls:

Range = 11

IQR = 6

Height of boys:

Range = 12

IQR = 4

Step-by-step explanation:

I placed the height of girls from lowest to greatest (49,49,52,53,53), 54, (57,57,58,58,60) then I subtracted 49 from 60. I subtracted 49 from 60 (60 - 49 = 11) because you subtract the smallest number in the data from the highest number to get the range. Now to find the IQR, you need to find the median. The median is the number right in the middle of the data so in this case it's 54. You can make parenthesis for the all the number behind and in front of the median like I did (You don't have to do it, it makes it easier for me to find the Q1 and Q3). You have to find the Q1 and Q3 which is in the middle of the numbers behind and after 54. For our Q1 it's 52 and for our Q3 it's 58. You can think of the Q1 and Q3 as a median or the middle number for the data. Just in case you need it I placed the Height of the boys here. (52, 54, 57, 58, 58,) 59, (59, 61, 61, 63, 64).

olga nikolaevna [1]3 years ago

4 0

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Read 2 more answers

Which value is equivalent to 48 ÷ ((2 + 6) × 2) − 1? A) -12 B) 2 C) 3 1 5 D) 3

timama [110]

Answer:

B) 2

Step-by-step explanation:

Given expression,

48 ÷ ((2 + 6) × 2) − 1

In simplification we follows the following order,

B = Bracket

O = Of

D = Division

M = Multiplication

A = Addition,

S = Subtraction,

Thus, steps of solving the given expression by following BODMAS are as follow,

$\frac{48}{(2 + 6) \times 2}-1$

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4 years ago

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3 years ago

(a) Let {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it app

Nataliya [291]

Answer:

0.625

Step-by-step explanation:

Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.

Since A1 and A2 are mutually exclusive and exhaustive, we can say

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c) Using Bayes theorem

conditional probability that it wasthe biased coin

= $\frac{0.375}{0.625} \\=\frac{3}{5}$

d) Given that the chosen coin flips tails,the conditional probability that it was the biased coin= $\frac{0.25*0.5}{0.25*0.5+0.5*0.5} \\=\frac{1}{3}$

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3 years ago