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vampirchik [111]
3 years ago
10

The product of two 2-digit factors whose product is greater than 200 but less than 600

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0
10 × 30 = 300
(20 characters thing)
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a spinner is divided into eight equal-sized sections, numbered from 1 to 8, inclusive. what is true about spinning the spinner o
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A spinner is divided into eight equal-sized
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2 years ago
What is the area of the triangle??? helpppp
MAVERICK [17]

Answer:

210 ft^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh where b is the base and h is the height

Since this is a right triangle  the base is 20 ft and the heigth is 21 ft

A = 1/2 ( 20) * 21

210 ft^2

4 0
3 years ago
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One third of the candidates for a job were 25 years old or younger. two sevenths of the candidates were at least 50 years old. i
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There are three groups of people: 25 years old and younger, between 25 to 50, and 50 years old and older. Their fractions must equal to 1 because these three together form the whole.

1 = 1/3 + 2/7 + x
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x = 8/21

So, the actual number of people ages 25 to 50 years old is:

84(8/21) = 32 people

7 0
4 years ago
What is parallel to 2x-y=1 and contains (4, -6)? Please show your work!
Contact [7]

k:\ y=m_1x+b_1\\\\l:\ y=m_2x+b_2\\\\l\ ||\ k\iff m_1=m_2\\\\\text{We have}\\\\k:\ 2x-y=1\ \ \ |-2x\\-y=-2x+1\ \ \ \ |\cdot(-1)\\y=2x-1\to m_1=2\\\\l:\ y=m_2x+b\\\\l\ ||\ k\iff m_2=2\\\\l:\ y=2x+b\\\\\text{The line l contains (4, -6)}\\\\\text{Put the values of coordinates to the equation of line l}\\\\-6=2(4)+b\\-6=8+b\ \ \ \ \ |-8\\b=-14\\\\Answer:\ y=2x-14\to 2x-y=14

5 0
3 years ago
RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly
tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

4 0
3 years ago
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