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Dahasolnce [82]
3 years ago
5

Car X travels 144 miles in 3 hours.

Mathematics
1 answer:
coldgirl [10]3 years ago
6 0

Answer:

A. Y = 48x

B. A distance and Tiem graph is a graph that represents the relationship because you can see how far it goes within a certain time and you can find out the speed of the vehicle D

---

T

Step-by-step explanation:

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I will give BRAINLIEST to the correct answer
erica [24]

Answer:

<PCH+<HCK=180-DEGREE BEING IN A STRAIGHT LINE.

3M+58+8M+155=180

11M=180-213

11M=-33

M=-3

SO,

<PCH

3M+58

=3*(-3)+58

=58-9

=49-DEGREE

7 0
3 years ago
A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
What is the answer to this question?
harina [27]

Answer:

f(g(0) )= -1

Step-by-step explanation:

Find g(0) = -1

Then find f(-1) = 1

f(g(0) )= -1

4 0
3 years ago
Factor the expression: 84x – 12x
liberstina [14]
Subtract 12x from 84x = 72x
6 0
3 years ago
Read 2 more answers
Multiply Conjugates <br><br><br><br><br> (r+1/4)r-1/4)
Mamont248 [21]

Answer:

\large\boxed{\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\dfrac{1}{16}}

Step-by-step explanation:

\text{Use}\ (a+b)(a-b)=a^2-b^2\\\\\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\left(\dfrac{1}{4}\right)^2=r^2-\dfrac{1^2}{4^2}=r^2-\dfrac{1}{16}

8 0
3 years ago
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