Answer:
The vertical line indicating bonds breaking
Explanation:
Answer:
The compound a is 1-methyl cyclohexene (see attachment for structure).
Explanation:
The reaction of 1-Bromo-1-methylcyclohexane with sodium methoxide is a <u>second-order reaction</u> since the <u>methoxide ion is a strong base</u> and also a strong nucleophile. This ion attacks the alkyl halide faster than the alkyl halide can ionize to produce a first-order reaction. However, we can not see the product of nucleophilic substitution. The SN₂ mechanism is blocked due to the <u>impediment of the 1-Bromo-1-methylcyclohexane</u>. The main product, according to the Zaitsev rule, is the 1-methyl cyclohexene, thus forming a <u>double bond</u>.
Then, this cyclohexene is hydrogenated to form the cyclohexane.
Answer:
Answer: A) .346 M
Explanation:
Given:
- 450 mL
- .5 M soln
-200 mL water
1) Convert mL to L
450 mL = .45 L
200 mL = .2 L
2) Find mols in solution
.5 M = x/.45 L
x = .225 mol
3) Find total volume of solution
.45 L + .2 L =.65 L
4) Find new molarity
molarity (M) = mols solute/ L solution
y = .225 mol (from step 2)/ .65 L (from step 3)
y = .346 M
Answer: A) .346 M
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