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Sauron [17]
3 years ago
11

A thermometer reads an outside air temperature of 35°c. What is the temperature in degrees Fahrenheit

Chemistry
1 answer:
Hoochie [10]3 years ago
3 0

35°c is equal to 95°f

To do this multiply 35 and 1.8

35 x 1.8=63

Now add 32

Resulting in the answer 95

(The equation for to solve for c and f is c1.8+32=f

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Please check this for me?
kolbaska11 [484]
The answer is 
<span>2PbS(s) + 3O2(g) = 2PbO(s) + 2SO2(g)

Your answer is not yet balanced because you have 3 oxygen atoms. it should be balanced by multiplying both side by 2 such as the balanced equation I made. To check it, I will explain why your answer is not yet balanced.

check: (from your equation)
</span> 1-Pb-1
 1-S-1
2 -O-3
the difference between the reactant and the product of Oxygen will prove that it is not yet balanced.

If you use 2PbS(s) + 3O2(g) = 2PbO(s) + 2SO2(g), to check it:
2-Pb-2
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6 -O-6
then this is now balance
6 0
3 years ago
Which of these is a chemical property?
ankoles [38]

Answer:

The second choice, or flammability.

Explanation:

The flammability of something is how easy it is for it to burn or ignite.

7 0
4 years ago
Read 2 more answers
how much energy must be released by 50.0 g of steam to decrease its temperature from 125.0 degrees Celsius to 100.0 degrees Cels
REY [17]

Answer:

5250 Joules

Explanation:

Mass = 50g

Initial Temperature = 125.0 degrees Celsius

Final Temperature =  100 degrees Celsius

Temperature change = Final - Initial = 100 - 125 = -25

Heat = ?

These quantities are related by the equation;

H = mCΔT

where c = specific hear capacity = 4.2 J/g°C

H = 50 * 4.2 *  (-25)

H = -5250 J (The negative sign is because heat is being released)

7 0
3 years ago
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harina [27]
First one……………………………….
6 0
3 years ago
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if i initially have 4.0 L of a gas at a pressure of 1.1 atm, what will the volume be if i increase the pressure to 3.4 atm
Lelechka [254]

Answer:

<h3>The answer is 1.29 L</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{4 \times 1.1}{3.4}  =  \frac{4.4}{3.4} \\   =1.294117647...

We have the final answer as

<h3>1.29 L</h3>

Hope this helps and

6 0
3 years ago
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