Remember:
6.022×10²³ molecules = 1 mol (Avogadro's number)
NH₃ = ammonia
To get molar mass of NH₃, add the mass of nitrogen + 3 times the mass of hydrogen (because there are 3 hydrogens in NH₃).
14.01 + 3(1.01) = 17.04 grams NH₃ = molar mass
1) Set up your equation. You want to cancel out molecules, and get to grams through moles.
So multiply 3.4×10²⁴ molecules of ammonia × 1 mol of ammonia × 17.04 grams of ammonia and divide it by 6.022×10²³ molecules of ammonia and 1 mol of ammonia.
3.4×10²⁴ molecules of ammonia × 1 mol of ammonia × 17.04 grams of ammonia
6.022×10²³ molecules of ammonia 1 mol of ammonia
Your answer should come out to be: 96.20724 grams of ammonia
Round to 2 sig figs: 96 grams of ammonia
I think it's coal as you use it for bbqs and train drivers use coal too. I'm pretty sure it's coal, but I'm not 100% sure. Hoped this helps.
First write the formula and make sure it is balance
MgSO4 + BaCl2 --> MgCl2 + BaSO4
then, we need to determine which reactant is the limiting reagent. using their respective molar masses.
1.20 g MgSO4 x (1 mole MgSO4/ 120.3 g)=0.00998 moles
10.0 g BaCl2 x (1 mole BaCl/ 172 g) = 0.0580 moles
Since MgSO4 give the less amount of moles, MgSO4 is the limiting reagent.
0.00998 moles MgSO4 (1 mole BaSO4/1 mole MgSO4) (233.3 g/ 1 mole BaSO4) = 2.34 grams
The element cesium forms a positive ion with the charge +1 . The symbol for this ion is Ce⁺, and the name is cesium ion. The number of electrons in this ion is 54.
<h3>What group does the element cesium belong to in the periodic table?</h3>
Cesium belong to the Group 1A of the periodic table.
Group 1A elements are known as alkali metals.
The alkali metals react with water to form alkalis. They form ions with a positive charge of +1 by the loss of an electron.
In conclusion, cesium is an alkali metals it belongs to group 1A of the periodic table. It forms a positive ion with a charge of +1 by the loss of an electron.
Learn more about alkali metals at: brainly.com/question/25317545
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4. emit more shortwave radiation than cooler objects do.