Answer:- 3333 g of solution.
Some of the question part is missing here. It would be like, "Determine the mass in grams of each NaCl solution that contains 1.5 g of NaCl.
(i) 0.045% NaCl by mass
Solution:- 0.045% NaCl by mass means 0.045 g of NaCl are present in 100 g of solution. 1.5 g of NaCl would be present in how many grams of solution?
We could solve this using proportions...
(0.045/100) = (1.5/X)
0.045(X) = 1.5(100)
0.045X = 150
X = 150/0.045 = 3333
So, 1.5 g of NaCl is present in 3333 g of solution.
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Answer:
3.6667
Explanation:
<u>For helium gas:</u>
Using Boyle's law
Given ,
V₁ = 3.0 L
V₂ = 9.0 L
P₁ = 5.6 atm
P₂ = ?
Using above equation as:
<u>The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm</u>
<u>For Neon gas:</u>
Using Boyle's law
Given ,
V₁ = 4.5 L
V₂ = 9.0 L
P₁ = 3.6 atm
P₂ = ?
Using above equation as:
<u>The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm</u>
<u>Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.</u>
Addition of boiled, deionized water to the titrating flask to wash the wall of the erlenmeyer flask and the buret tip will have no effect on the Ksp value of ca(oh)2.
There will be no effect on the Ksp value as boiled deionised water is not able to alter the number of hydronium and hydroxide ions. As no change in the ions happen so there will be no change in Ksp value. The equilibrium constant for a solid material dissolving in an aqueous solution is the solubility product constant, Ksp. It stands for the degree of solute dissolution in solution. A substance's Ksp value increases with how soluble it is.
To know more about, solubility product constant, click here,
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