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mezya [45]
3 years ago
11

BRT,DBF,HIL,NPR,.....

Mathematics
1 answer:
Sergio039 [100]3 years ago
4 0
OSOSPWBSWR F SDOSOEPW.,
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The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin
quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

<u>So, </u>According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of <u>The inscribed circle</u>

<u>So, the center of The inscribed circle is the point S</u>

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

<u>So,</u> According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of <u>The circumscribed circle</u>

<u>So, the center of The circumscribed circle is the point P</u>

5 0
3 years ago
PLEASEEEEE HELP FOR 15 POINTS AND BRAINLIEST
galina1969 [7]
The balance in dollars at the end of 4 years will be $1,462.50
8 0
3 years ago
Solve the system of linear equations below.
Reika [66]

Answer:

x = 1 , y = 3 thus: A is your Anser

Step-by-step explanation:

Solve the following system:

{2 x + y = 5 | (equation 1)

x + y = 4 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y = 5 | (equation 1)

0 x+y/2 = 3/2 | (equation 2)

Multiply equation 2 by 2:

{2 x + y = 5 | (equation 1)

0 x+y = 3 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 2 | (equation 1)

0 x+y = 3 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 1 | (equation 1)

0 x+y = 3 | (equation 2)

Collect results:

Answer:  {x = 1 , y = 3

8 0
3 years ago
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Can someone remind me how to add negative and positive numbers together along with subtracting them correctly? Please provide ex
Zarrin [17]
To add a negative and a positive I usually just subtract them so ex: -5+4=-1
and to subtract them I add the numbers together so -5-4=-9 so its basically the opposite   
7 0
4 years ago
A rabbit hopped 11 meters in 6 minutes. At that rate, how far did the rabbit hop in 8 minutes?
ad-work [718]
It hopped 14 meters in 8 minutes.
6 0
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