Answer:
230 were sold at the door
170 were sold in advance
Step-by-step explanation:
x=at door y=in advance
x+y=400
3x+2y=1030
y=-x+400
2y=-3x+1030
y=-3/2x+515
-x+400=-3/2x+515
x=230 y=170
Answer:Sure thing? But first what do you need help with and maybe just maybe I will help you with whatever you need help with?
Step-by-step explanation:
Answer:

so at the long run we can conclude that the best option is :
A) win 0.20 cents per play
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
Let X the random variable who represent the ampunt of money win/loss at the game defined.
The probability of loss $3.00 for this game is 0.2 and the probability of win is 1-0.2=0.8 and you will recieve $1.00 if you win. The expected value is given by:

And for this case if we replace we got:

so at the long run we can conclude that the best option is :
A) win 0.20 cents per play
Answer:
(a) 6.01 (b) 57.33
Step-by-step explanation:
(a) DF² = 10² + 12² - 2 · 10 · 12 · cos(30°)
=> DF² = 244 - 240 · cos(30°)
=> DF² = 36.154
=> DF = √36.154
=> DF ≈ 6.01
(b)
=> sin (B) = sin (63) × 12.4 ÷ 12.8
=> B = sin^-1 (sin (63) × 12.4 ÷ 12.8)
=> B = 59.67355245
180 - 63 - 59.67355245 ≈ 57.33
Law of cosines & sines:
sqrt (18y10) =
3 y5 • sqrt(2)