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Masteriza [31]
3 years ago
7

Is the function even or odd?

Mathematics
1 answer:
sweet [91]3 years ago
6 0

Answer:

f(\theta)=\cos(\theta) is an even function.

Step-by-step explanation:

Recall when it means when a function is even or odd. An even function has the following property:

f(-x)=f(x)

And an odd function has the following property:

f(-x)=-f(x)

So, let's test some values for cos(x).

Let's use π/3:

f(\pi/3)=\cos(\pi/3)

From the unit circle, was can see that this is 1/2 (refer to the x-coordinate).

Now, let's find -π/3. This is the same as 5π/3. Thus:

f(-\pi/3)=\cos(-\pi/3)

And again from the unit circle, we can see that this is 1/2.

Therefore, despite the negative, the function outputs the same value.

Cosine is an even function.

Notes:

Cosine is an even function and sine is an odd function. It's helpful to remember these as they can help you solve some trig problems!

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The following picture is a square pyramid where DE=8 cm and m∠ADE=60°.
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<u>Given</u>:

The length of DE is 8 cm and the measure of ∠ADE is 60°.

We need to determine the surface area of the pyramid.

<u>Length of AD:</u>

The length of AD is given by

cos 60^{\circ}=\frac{FD}{8}

       4=FD

Length of AD = 8 cm

<u>Slant height:</u>

The slant height EF can be determined using the trigonometric ratio.

Thus, we have;

     sin \ 60^{\circ}=\frac{EF}{8}

sin \ 60^{\circ} \times 8=EF

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Thus, the slant height EF is 4√3

<u>Surface area of the square pyramid:</u>

The surface area of the square pyramid can be determined using the formula,

SA=Area \ of \ square + \frac{1}{2} (Perimeter \ of \ base ) (slant \ height)

Substituting the values, we have;

SA=8^2+\frac{1}{2}(8+8+8+8)(4 \sqrt{3})

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SA=64+(16)(4 \sqrt{3})

SA=64+64 \sqrt{3}

The exact form of the area of the square pyramid is 64+64 \sqrt{3}

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SA = 64 + 110.848

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Rounding off to one decimal place, we get;

SA = 174.8

Thus, the area of the square pyramid is 174.8 cm²

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