Answer:
1) 20.9
2) 896
3) 21
Step-by-step explanation:
1) 5.6÷2^3+(12.75+7.45)
---> 12.75 + 7.45 = 20.2
÷ 
--> Simplify 2^3 to 8
÷ 8 + 20.2
--> 5.6 ÷ 8 = 0.7
--> Simplify
2) 4^3 × (0.6 +3.6) ÷ 0.3
---> 0.6 + 3.6 = 4.2
4^3 * 4.2 ÷ 0.3
---> 4^3 = 64
64 * 4.2 ÷ 0.3
--> 64 * 4.2 = 268.8
268.8 ÷ 0.3
--> 268.8 ÷ 0.3 = 896
896
3) 2^4 + (2.75 +1.75) ÷ 0.9
--> 2.75 + 1.75 = 4.5
2^4 + 4.5 ÷ 0.9
--> 2^4 = 16
16 + 4.5 ÷ 0.9
--> 4.5 ÷ 0.89 = 5
16 + 5
--> Simplify
= 21
You divide by the 2x by 5 and thats your answer :)
Answer:
sure ill help
Step-by-step explanation:
Answer:
(a) true
(b) true
(c) false; {y = x, t < 1; y = 2x, t ≥ 1}
(d) false; y = 200x for .005 < |x| < 1
Step-by-step explanation:
(a) "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...
s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m
This equation matches the form of a function periodic with period 2T.
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(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:
s(a) +s(b) = s(a+b) . . . . definition of linear function
Then if a=b, you have
2s(a) = s(2a)
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(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.
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(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.
9 is subtracted from the sum of 5 and a number
