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11Alexandr11 [23.1K]
3 years ago
11

What is the equation of the line in point-slope form that has a slope of -3 and passes through the point (5, 9)?

Mathematics
1 answer:
otez555 [7]3 years ago
3 0

Answer:

try = (-10/11)x - (49/11)

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slega [8]

Answer:

The equation to this question is "x^2+y^2=16"

Step-by-step explanation:

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\to  r(t) = 4 \cos (t)i + 4 sin(t)j + k\\where \\\\\to x(t)= 4 \cos t\\\to y(t) = 4 \sin t\\\to z(t)=1\\

\to x^2+y^2= 16 \cos^2 t +16 \sin^2 t\\\\\to x^2+y^2= 16 (\cos^2 t +\sin^2 t)\\\\\therefore (\cos^2 t +\sin^2 t =1)\\\\\to x^2+y^2= 16 (1)\\\\\to x^2+y^2= 16\\\\\to z=1

 So, the curve r(t) = 4 \cos (t)i + 4 sin(t)j + k is basically a circle, which is defined in the attachment file.

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Answer:

660.4

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