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blsea [12.9K]
3 years ago
5

1. Suppose that I'm flipping a dime and quarter, such that the probability that both are head is pi, both tail is P2, only the d

ime is head is p3, and only the quarter is head is 1- P1 – P2 - p3. The entropy (or randomness) of this two-coin-flip is H(P1, P2, P3) = -pı log2 (P1) – P2 log2 (P2) – P3 log2 (P3) – (1 – P1 – P2 - P3) log2(1 – P1 – P2 - P3). Calculate a H/Op1, and evaluate it at P1 = P2 = P3 = 0.25 and at pı = 0.7, P2 = P3 = 0.1. 2. Compute the Hessian of the following functions, and verify directly that the matrix is symmetric: (a) u(x, y) = y*exy, (b) v(x, y, s) = 114,22 3. I'm climbing a mountain, whose landscape is described by the function z(x, y) = e-(x++y). I'm at position (x, y) = (-1,1). What is the maximal slope at this point? What is the slope I'm climbing if I walk southwest?
Mathematics
1 answer:
ANEK [815]3 years ago
6 0

What are the options ???

Step-by-step explanation:

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Which ordered pair is a solution to the system of inequalities graphed here?
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Answer: I dont know

Step-by-step explanation:

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The volume of a sphere is increasing at a rate of 7 cm3/sec. Find the rate of change of its surface area when its volume is cm3.
mafiozo [28]

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A square is divided into nine smaller squares of equal area. The center square is then divided into nine smaller squares of equa
Schach [20]

Answer:

1/2 of the figure is shared

Step-by-step explanation:

From the attachment, 4 out of the 8 squares are shaded

The center square which makes it the 9th is subdivided into 9 squares again.

The pattern of division continues indefinitely.

In every subdivision, 4 squares are shaded leaving the other 4 squares white while the 9th(center square) forms another subdivision.

Therefore, it can be concluded that 1/2 of the figure is shaded.

8 0
3 years ago
4+(-3)
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4 0
3 years ago
The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab
erastova [34]

Answer:

the probability that the sample mean will be larger than 1224 is  0.0082

Step-by-step explanation:

Given that:

The SAT scores have an average of 1200

with a  standard deviation of 60

also; a sample of 36 scores is selected

The objective is to determine  the probability that the sample mean will be larger than 1224

Assuming X to be the random variable that represents the SAT score of each student.

This implies that  ;

S \sim N ( 1200,60)

the probability that the sample mean will be larger than 1224 will now be:

P(\overline X > 1224) = P(\dfrac{\overline X - \mu }{\dfrac{\sigma}{\sqrt{n}} }> \dfrac{}{}\dfrac{1224- \mu }{\dfrac{\sigma}{\sqrt{n}} })

P(\overline X > 1224) = P(Z > \dfrac{1224- 1200 }{\dfrac{60}{\sqrt{36}} })

P(\overline X > 1224) = P(Z > \dfrac{24 }{\dfrac{60}{6} })

P(\overline X > 1224) = P(Z > \dfrac{24 }{10} })

P(\overline X > 1224) = P(Z > 2.4 })

P(\overline X > 1224) =1 -  P(Z \leq 2.4 })

From Excel Table ; Using the formula (=NORMDIST(2.4))

P(\overline X > 1224) = 1 -  0.9918

P(\overline X > 1224) = 0.0082

Hence;  the probability that the sample mean will be larger than 1224 is  0.0082

4 0
3 years ago
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