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blsea [12.9K]
4 years ago
5

1. Suppose that I'm flipping a dime and quarter, such that the probability that both are head is pi, both tail is P2, only the d

ime is head is p3, and only the quarter is head is 1- P1 – P2 - p3. The entropy (or randomness) of this two-coin-flip is H(P1, P2, P3) = -pı log2 (P1) – P2 log2 (P2) – P3 log2 (P3) – (1 – P1 – P2 - P3) log2(1 – P1 – P2 - P3). Calculate a H/Op1, and evaluate it at P1 = P2 = P3 = 0.25 and at pı = 0.7, P2 = P3 = 0.1. 2. Compute the Hessian of the following functions, and verify directly that the matrix is symmetric: (a) u(x, y) = y*exy, (b) v(x, y, s) = 114,22 3. I'm climbing a mountain, whose landscape is described by the function z(x, y) = e-(x++y). I'm at position (x, y) = (-1,1). What is the maximal slope at this point? What is the slope I'm climbing if I walk southwest?
Mathematics
1 answer:
ANEK [815]4 years ago
6 0

What are the options ???

Step-by-step explanation:

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PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!
77julia77 [94]

Answer:

$125

Step-by-step explanation:

To solve this, we need to find 2.5% of 5,000. To do this, we multiply 5,000 by .025. This gets us 125. That means you earn $125 worth of interest in one year.

7 0
3 years ago
Read 2 more answers
The side of an Equileteral triangle is 12cm. What is its Area?
elena55 [62]

Answer:

A = 62.35 cm²

Step-by-step explanation:

Use the area formula A = \frac{\sqrt{3}a^2}{4}, where a is the side length.

Plug in the values:

A = \frac{\sqrt{3}(12^2)}{4}

A = \frac{\sqrt{3}(144)}{4}

A = 62.35 cm²

3 0
4 years ago
I need help on this pls answer
Anastaziya [24]

Answer:

144500

Step-by-step explanation:

(1.7 x 10^4) x (8.5 x 10^-2)

= (1.7 x 10000) x (8.5 x 0.01)

=( 17/10 x 10000/1) x (17/2 x 1/100)

=17000/1 x 17/200

=289000/2

=1445000

6 0
2 years ago
Can some one help meeee
Strike441 [17]

Answer:

With what? there is nothing here

Step-by-step explanation:

6 0
3 years ago
How do you solve √125÷√5​
nordsb [41]

\bf \sqrt{125}\div \sqrt{5}\implies \cfrac{\sqrt{125}}{\sqrt{5}}\qquad \begin{cases} 125=&5\cdot 5\cdot 5\\ &5^2\cdot 5 \end{cases}\implies \cfrac{\sqrt{5^2\cdot 5}}{\sqrt{5}} \\\\\\ \cfrac{5~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 5

8 0
3 years ago
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