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3 years ago

Please help ASAP!!!! Will give brainlist :)

Mathematics

1 answer:

almond37 [142]3 years ago

7 0

Answer:

(D) Each year,the machinery loses a value of 4,500

When it is 3 years old,it is worth a little over 35K ,and when it is 6 years old,its worth about 22K.

This info means A,C and B is wrong b/c it loses too little value per year.

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F(x)=4x4−5x3−2x+6 and g(x)=3x3−4x2−2x+1 . What is f(x)+g(x) ?

igomit [66]

4*4-5*3-2x+6= -x-7/2 slope = 2

3 * 3 - 4 *2 -2x +1= - x - 2/2 slope = -2

2 + -2 = 0

6 0

3 years ago

-12<-6x please help

pishuonlain [190]

-12 < -6x

-12/-6 > x divide both sides by -6

12/6 > x two negatives makes a positive

2 > x simplify

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hope this helps, God bless!

6 0

3 years ago

If the level of significance (alpha) is 0.05, it means that the probability of rejecting the null hypothesis, when it is false,

Kaylis [27]

Answer: The probability of rejecting the null hypothesis, when it is true, is 5%.

Step-by-step explanation:

We know that the level of significance ( denoted as $\alpha$ ) is generally the probability of rejecting the null hypothesis when it is true.

Therefore , If the level of significance (\alpha[/tex] ) 0.05, then it means that it is the probability of rejecting the null hypothesis when it is true.

i.e. The probability of rejecting the null hypothesis when it is true= 0.05

In percent : $0.05=5\%$

Hence, the correct option is : The probability of rejecting the null hypothesis when it is true is 5%.

4 0

3 years ago

The question is below (This an order of operation question)

olga_2 [115]

Step-by-step explanation:

i am 90% sure this is correct

7 0

3 years ago

Read 2 more answers

An individual who has automobile insurance from a certain company is randomly selected. Let y be the number of moving violations

Hoochie [10]

Answer:

a) $E(Y)= \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95$

b) $E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148$

Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.

Solution to the problem

Part a

We have the following distribution function:

Y 0 1 2 3

P(Y) 0.45 0.2 0.3 0.05

And we can calculate the expected value with the following formula:

$E(Y)= \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95$

Part b

For this case the new expected value would be given by:

$E(80Y^2)= \sum_{i=1}^n 80Y^2_i P(Y_i)$

And replacing we got

$E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148$

5 0

3 years ago