The emf of a cell is mathematically given as
= 0.0532 v
<h3>What is the emf of a cell?</h3>
Generally, the equation for emf is mathematically given as
where,
Pb is lead
H is hydrogen
/ Pb has a standard reduction potential of -0.126 volts, while
/ has a standard reduction potential of 0.0 volts.
![[Pb^2^+] x [H^+]^2](https://tex.z-dn.net/?f=%5BPb%5E2%5E%2B%5D%20x%20%5BH%5E%2B%5D%5E2)
= 0.126 - 0.059/2 log 1 / [0.57] x [0.09]^2
= 0.0532 v
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Answer:
1519
Step-by-step explanation:
if wrong super sooryyyyy :(
This is a quotient (division) of two functions we must be concerned with the fact that division by zero is undefined.
Since g(x) is in the divisor position, it cannot equal 0.
Subtract 6 from both sides to solve.
So the domain is all real numbers except -6
Set notation {x | x ∈ R, x ≠ -6}
Interval notation (-∞,-6)∪(-6,∞)
