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3 years ago

5

Please help me I have no idea how to solve!

1 answer:

irinina [24]3 years ago

3 0

Step-by-step explanation:

It says add across to the right and add down bottom

Add across

$3x$ $2x^2$ $3x +2x^2$

$x^2$ $5x$ $x^2 + 5x$

Add down $3x + x^2$ $2x^2 +5x$ $3x^2 +8x$

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The ratio of the number of apples to the number of pears in a basket was 3:5. After 7more apples were added to the basket and 9

atroni [7]

Answer:

Apples = 24

Pears = 40

Step-by-step explanation:

Let u be the unit of fruit in the basket,

number of apples: $3u +7$

number of pears: $5u -9$

now to find u, we equate the two equations.

$3u+7=5u-9$

Now simplify.

$5u-3u=7+9$

$2u=16$

$u=8$

Now we can find the original number of apples and pears by substituting u.

so original number of apples = $3u = 3(8) = 24$

and original number of pears = $5u = 5(8) = 40$

5 0

4 years ago

Strong positive<br> strong negative<br> weak positive<br> weak negative

Nesterboy [21]

If you're looking for the trend name, I would say Strong Positive, or (a).

6 0

3 years ago

Further analysis of the data for the breakfast cereals in exercise 46 looked for an assocation between fiber content and calorie

photoshop1234 [79]

Complete Question:

Attached below as picture.

Answer:

From first graph there is no linear pattern so here linearity assumption violated.

From second graph there is observation is in some pattern like funnel or v shape so there is no constant variance occur that is there is no constant variance for error.

Constant variance for error occur when in residual plot all observation are in scatter everywhere.

From third graph we can say there is positive distribution but for regression analysis we need symmetric that is normal distribution.

Step-by-step explanation:

See graphs attached below.

8 0

3 years ago

Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?

Phantasy [73]

Answer:

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Step-by-step explanation:

Given : $\cos (180^{\circ}-q)=-\cos q$

We have to write which identity we will use to prove the given statement.

Consider $\cos (180^{\circ}-q)=-\cos q$

Take left hand side of given expression $\cos (180^{\circ}-q)$

We know

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Comparing , we get, a= 180° and b = q

Substitute , we get,

$\cos (180^{\circ}-q)=\cos 180^{\circ} \cos (q)+\sin q \sin 180^{\circ}$

Also, we know $\sin 180^{\circ}=0$ and $\cos 180^{\circ}=-1$

Substitute, we get,

$\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0$

Simplify , we get,

$\cos (180^{\circ}-q)=-\cos (q)$

Hence, use difference identity to prove the given result.

7 0

3 years ago

Read 2 more answers

.…: need this answers.....

Leto [7]

Sorry, cannot just give you answers without your input.
I'd suggest that you look up online or in your textbook each of the items under "Type of Boundary." The results you'd get will likely help you fill in the rest of the boxes.

3 0

3 years ago