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2 years ago

What is the range of the function y=3x-2 if the domain is {0,1,2}

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

4 0

Answer: 2

Step-by-step explanation:

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I need some help please

gizmo_the_mogwai [7]

Answer:

a) -10

b) 7

Step-by-step explanation:

a) $2(x + 3) = x - 4$

$= > 2x + 6 = x - 4$

$= > 2x - x = - 4 - 6$

$= > x = - 10$

b) $4(5x - 2) = 2(9x + 3)$

$= > 20x -8 = 18x + 6$

$= > 20x - 18x = 8 + 6$

$= > 2x = 14$

$= > x = \frac{14}{2} = 7$

3 0

3 years ago

Read 2 more answers

The standard form of a linear equation is Ax + By = C. Rewrite this equation in slope-slope-intercept form. What is the slope? W

myrzilka [38]

Standard form is Ax + By = C, or By = C - Ax.

Dividing both sides by B, we get y = C/B - (A/B)x

Here the y intercept is C/B, and the slope is -A/B.

4 0

3 years ago

Solve the inequality n + 20 < -42, and write the solution in interval notation.

Firdavs [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

The equation c=6.4w represents the cost c for w pounds of walnuts. Does a value of 2.5 for w make sense in this situation? Expla

sineoko [7]

We are given equation: c=6.4w, where the cost c for w pounds of walnuts.

w represents the number of pounds of walnuts.

Number of pounds could be in decimals.

The value of w = 2.5 represents 2.5 pounds of walnuts.

On plugging w=2.5 in c=6.4w equation, we get.

c=6.4×2.5 = $16.

Therefore, for 2.5 pounds of walnuts the total cost is $16.

Hence, a value of 2.5 for w make sense in this situation. It shows that cost of 2.5 pounds of walnuts is $16, where cost of each pound of walnuts is 6.4.

6 0

2 years ago

Slove the simoltanous equation by using substitution or elimination method 5x-3y=1 3x+2y=1

xxTIMURxx [149]

By substitution method 

5x - 3y =1

3x + 2y = 1

_____o____o____

$5x - 3y = 1 \\ 5x = 1 + 3y \\ x = \frac{1 + 3y}{5}$

______o____o_____

$3x + 2y = 1 \\ 3( \frac{1 + 3y}{5} ) + 2y = 1 \\ \frac{3 + 9y}{5} + 2y = 1 \\ \frac{3 +9y + 10y}{5} = 1 \\ \frac{3 + 19y}{5} = 1 \\ 3 + 19y = (1)(5) \\ 3 + 19y = 5 \\ 19y = 5 - 3 \\ 19y = 2 \\ y = \frac{2}{19}$

______o_____o____

$x = \frac{1 + 3y}{5} = \frac{1 + 3 \frac{2}{19} }{5} \\ x = \frac{1 + \frac{6}{19} }{5} = \frac{ \frac{19 + 6}{19} }{5} = \frac{ \frac{25}{19} }{5} \\ x = \frac{25}{19} \div 5 \\ x = \frac{25}{19} \times \frac{1}{5} \\ x = \frac{5}{19}$

I hope I helped you^_^

7 0

2 years ago