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Degger [83]
2 years ago
10

What is the range of the function y=3x-2 if the domain is {0,1,2}

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
4 0

Answer: 2

Step-by-step explanation:

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I need some help please
gizmo_the_mogwai [7]

Answer:

a) -10

b) 7

Step-by-step explanation:

a) 2(x + 3) = x - 4

=  > 2x + 6 = x - 4

=  > 2x - x =  - 4 - 6

=  > x =  - 10

b) 4(5x - 2) = 2(9x + 3)

=  > 20x -8 = 18x + 6

=  > 20x - 18x = 8 + 6

=  > 2x = 14

=  > x =  \frac{14}{2}  = 7

3 0
3 years ago
Read 2 more answers
The standard form of a linear equation is Ax + By = C. Rewrite this equation in slope-slope-intercept form. What is the slope? W
myrzilka [38]
Standard form is Ax + By = C, or By = C - Ax.

Dividing both sides by B, we get y = C/B - (A/B)x

Here the y intercept is C/B, and the slope is -A/B.


4 0
3 years ago
Solve the inequality n + 20 < -42, and write the solution in interval notation.
Firdavs [7]

Answer:

Step-by-step explanation:

4 0
3 years ago
The equation c=6.4w represents the cost c for w pounds of walnuts. Does a value of 2.5 for w make sense in this situation? Expla
sineoko [7]

We are given equation: c=6.4w, where the cost c for w pounds of walnuts.

w represents the number of pounds of walnuts.

Number of pounds could be in decimals.

The value of w = 2.5 represents 2.5 pounds of walnuts.

On plugging w=2.5 in c=6.4w equation, we get.

c=6.4×2.5 = $16.

Therefore, for 2.5 pounds of walnuts the total cost is $16.

Hence, <u>a value of 2.5 for w make sense in this situation. It shows that cost of 2.5 pounds of walnuts is $16, where cost of each pound of walnuts is 6.4.</u>


6 0
2 years ago
Slove the simoltanous equation by using substitution or elimination method 5x-3y=1 3x+2y=1<br>​
xxTIMURxx [149]

<u>By substitution method </u>

5x - 3y =1

3x + 2y = 1

_____o____o____

5x - 3y = 1 \\ 5x = 1  +  3y \\ x =  \frac{1 + 3y}{5}

______o____o_____

3x + 2y = 1 \\ 3( \frac{1 + 3y}{5} ) + 2y = 1 \\  \frac{3 + 9y}{5}  + 2y = 1 \\  \frac{3 +9y + 10y}{5}  = 1 \\  \frac{3 + 19y}{5}  = 1 \\ 3 + 19y = (1)(5) \\ 3 + 19y = 5 \\ 19y = 5 - 3 \\ 19y = 2 \\ y =  \frac{2}{19}

______o_____o____

x =  \frac{1 + 3y}{5}  =  \frac{1 + 3 \frac{2}{19} }{5} \\ x =  \frac{1 +  \frac{6}{19} }{5}  =  \frac{ \frac{19 + 6}{19} }{5}   =  \frac{ \frac{25}{19} }{5}  \\ x =  \frac{25}{19}  \div 5 \\ x =  \frac{25}{19}  \times  \frac{1}{5}  \\ x =  \frac{5}{19}

I hope I helped you^_^

7 0
2 years ago
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