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2 years ago

4. At Sports Shoe Warehouse, the cost of 9 pairs of baseball shoes is $855 plus $92 for each additional pair.

Mathematics

1 answer:

jonny [76]2 years ago

8 0

Answer:

10.46

Step-by-step explanation:

Let the Number of additional pair = x

Ware house A :

855 + 92x - - - (1)

Warehouse B:

Initial cost per pair before 9

= 810 / 9 = $90

Additional 7% for pairs after 9

1.07 * 90 = 96.3

810 + 96.3x - - - (2)

810 + 96.3x = 855+ 92x

96.3x - 92x = 855 - 810

4.3x = 45

x = 45 / 4.3

x = 10.46

Additional pair be 10.46

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3 years ago

NO is parallel to ML. How long is OL? 2/3ft 6ft 8ft 12ft

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Answer:

Step-by-step explanation:

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2 years ago

A plane rises from take-off and flies at an angle of 9 degrees with the horizontal runway. When it has gained 500 feet, find t

Len [333]

Answer:

The dashed hypotenuse measures: 3,205.13 ft.

Step-by-step explanation:

. B (Plane is here)

. .

A . . . . . . . C

BC = 500 ft

Angle (Ф) between AB and AC = 9 degrees

So,

Sin(Ф) = BC/AB

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3 years ago

How many randomly chosen guests should I invite to my party so that the probability of having a guest with the same birthday as

dimulka [17.4K]

Answer:

At least 401 chosen guests

Step-by-step explanation:

Represent those with same birth day with Same

So:

$P(Same) > \frac{2}{3}$

Represent number of people with n

There are 365 days in a year and 364 days out of these days is not your birthday.

So, there the probability that n people do not share your birthday is $(\frac{364}{365})^n$

i.e.

$P(none) = (\frac{364}{365})^n$

Solving further, we have that:

$P(same) + P(none) = 1$

$P(same) + (\frac{364}{365})^n = 1$

$P(same) = 1 - (\frac{364}{365})^n$

We're calculating the probability that $P(Same) > \frac{2}{3}$ .

So, we have:

$1 - (\frac{364}{365})^n > \frac{2}{3}$

Collect Like Terms

$1 - \frac{2}{3}> (\frac{364}{365})^n$

$\frac{3-2}{3}> (\frac{364}{365})^n$

$\frac{1}{3}> (\frac{364}{365})^n$

$3^{-1} > (\frac{364}{365})^n$

Take natural logarithm (ln) of both sides

$ln(3^{-1}) > ln((\frac{364}{365})^n)$

$-ln\ 3 > n\ ln\ (\frac{364}{365})$

Apply laws of logarithm

$-ln\ 3 > n\ (ln(364) - ln(365))$

Multiply through by -1

$ln\ 3 < n\ (ln(365) - ln(364))$

Solve for n

$\frac{ln\ 3}{(ln(365) - ln(364))} < n$

Reorder

$n > \frac{ln\ 3}{(ln(365) - ln(364))}$

$n > \frac{1.09861228867}{(5.89989735358 - 5.89715386764)}$

$n> \frac{1.09861228867}{0.00274348594}$

$n > 400.443928891$

$n > 400$ (approximated)

This implies that n = 401, 402, 403 .....

i.e

$n \geq 401$

So, at least 401 people has to be invited

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3 years ago