Answer:
The constant of variation is 5.
Step-by-step explanation:
In direct variation, as y varies directly with x, the standard equation is
y = kx,
where k is the constant of variation.
In your case, we use R and S. R varies directly with S, so we have
R = kS
We know that when S = 16, R is 80, so we plug in those values and solve for k, the constant of variation.
R = kS
80 = k(16)
k = 80/16
k = 5
Answer:
2.56
Step-by-step explanation:
Answer:
i think that 1, 3 and 4 are correct !!
Step-by-step explanation:
youre welcome, have a nice day!
NOTE: next time please provide the list of choices so it can be easier to help you
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
