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ICE Princess25 [194]
3 years ago
14

4. B А. Angle A is 135º. What is angle B? (show math and explain why)

Mathematics
1 answer:
ziro4ka [17]3 years ago
6 0
Where is the angle b???
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OPENER: Select all the names for the answers to a polynomial equation
alexira [117]
Roots stems finite solution
6 0
3 years ago
Which ordered pair is a solution of the equation
andrew11 [14]
(0,-7)
-7=11(0)+4
-7=0+4
-7 is not 4 -----not a solution

(-1,-7)
-7=11(-1)+4
-7=-11+4
-7=-7 ----solution

(1,-7)
-7=11(1)+4
-7=11+4
-7=15
-7 is not 15 ----not a solution

(2,26)
26=11(2)+4
26=22+4
26=26 ----soltion

(-1, -7) & (2, 26) are solutions to the equation
4 0
3 years ago
Based on the graphs of f (x) and g(x), what must the domain of (f ⋅ g)(x) be?
bekas [8.4K]

Using the concept of domain, the domain of (f.g)(x) is given by:

{x ∈ ℝ | x ≠ 3}

---------------------

  • The domain of a function is given by all possible input values, that is, <u>on a graph, all values that the x-axis assumes.</u>
  • In the graph, <u>function f assumes all real values.</u>
  • Function g is not defined for x = 3, thus, it's domain is all real values except 3.
  • Thus, the multiplication, as fg(x) = f(x) \times g(x), will also not be defined at x = 3, and the domain of the multiplication is:

{x ∈ ℝ | x ≠ 3}

A similar problem is given at brainly.com/question/4175434

4 0
3 years ago
The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.
Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let \mu = <u><em>population mean score</em></u>

So, Null Hypothesis, H_0 : \mu \leq 29.5      {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, H_A : \mu > 29.5      {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean MCAT score = 32.2

            s = sample standard deviation = 4.2

            n = sample of students = 40

So, <u><em>the test statistics</em></u> =  \frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }  ~  t_3_9

                                    =  4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0
3 years ago
A recipe calls for the following ingredients. 3 C flour, 1/2 t salt, 3/4 c sugar, 4 C fruit, 2 t butter.to make 2/3 of the recip
Hatshy [7]

Divide by 3 to each ingredient (gives you a third)  and then multiply your answer by two (gives you 2/3). For example, 2 divided by 3 is 2/3, multiply by two and get 1 1/3 t of butter. For the fruits, 4 divided by 3 is 4/3, simplified is 1 1/3, multiply by 2 and get 2 2/3.

8 0
3 years ago
Read 2 more answers
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