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KonstantinChe [14]
2 years ago
10

NEED HELP ITS A TEST!

Mathematics
1 answer:
jeka942 years ago
5 0

Answer:

X = -2 - y/3

Step-by-step explanation:

First you need to know the current equation, for that:

Notice that when Y = 0, X = 2.

When Y = 6, X = 0

Therefore the equation is X = 2-\frac{y}{3}

To move that to the left of the X axis (negative direction) you just have to reduce the X number:

x=-2 - \frac{y}{3}

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The perimeter of a rectangular pool is 288 m.
jolli1 [7]

Answer: 86

Step-by-step explanation:

8 0
2 years ago
In a collection of nickels, dimes, and quarters worth $6.90, the ratio of the number of nickels to dimes is 3:8. The ratio of th
dimulka [17.4K]
N=number of nickels
d=number of dimes
q=number of quarters

example
if n:d=3:8
lets say n=3 and d=8
3*8=8*3
so
8n=3d
slightly confusing but go with it, it migh make sense or it might not


n:d=3:8
8n=3d

d:q=4:5
5d=4q

solve for one of them
solve for nickels in first and quarters in second

8n=3d, n=(3/8)d
5d=4q, (4/5)d=q

5n+10d+25q=690
divide by 5 to make it easeir
n+2d+4q=138
sub (3/8)d for n
sub (4/5)d for q
(3/8)d+2d+5(5/4)d=138
(3/8)d+2d+25/4d=138

3/8+2+25/4=
3/8+16/2+50/8=
69/8

(69/8)d=138
times both sides by 8
69d=1104
divide both sides by 69
d=16

16 dimes
sub back

(5/4)d=q
(5/4)16=q
80/4=q
20=q

(3/8)d=n
(3/8)16=n
48/8=n
6=n



6 nickles
16 dimes
20 quarters
yah
8 0
3 years ago
In a class 28 of students, 5 have a cat and 21 have a dog. There are 4 students who do not have a cat or a dog. What is the prob
Sergeeva-Olga [200]

Answer:

15 have only a dog

5 have a dog and a cat

9 have only a cat

Step-by-step explanation:

20 + 14 = 34, there there are only 29 students, so 34 - 29 or 5 have both a dog and a cat

15 have only a dog

5 have a dog and a cat

9 have only a cat

6 0
3 years ago
The meaning of the graph suggested by the graph line is
madam [21]

Answer:c

Step-by-step explanation:

.

3 0
2 years ago
Read 2 more answers
In how many ways can a committee of 3 men and 2 women be formed from a group of 9 men and 10 ​women?
Setler [38]

Answer:

first you have to find the number of ways 3 men can be chosen, then the number of ways 2 women can be chosen, and then you need to multiply these numbers together to get the number of ways because multiplication will show the total arrangements possibilities. use combination since order does not matter.

number ways for 2 out of 10 women total: 10 choose 2= 45

number of ways for 3 out of 9 men total: 9 choose 3= 84

84x45= 3780

3780 total ways

number of ways

6 0
2 years ago
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