NEED HELP ITS A TEST!

Mathematics

1 answer:

jeka942 years ago

5 0

Answer:

X = -2 - y/3

Step-by-step explanation:

First you need to know the current equation, for that:

Notice that when Y = 0, X = 2.

When Y = 6, X = 0

Therefore the equation is X = $2-\frac{y}{3}$

To move that to the left of the X axis (negative direction) you just have to reduce the X number:

$x=-2 - \frac{y}{3}$

You might be interested in

N is an integer s=1/2 n(n+1) prove that 8s + 1 is an odd square number

pychu [463]

$s=\frac{1}{2}n(n+1) \\ \\
8s+1=8 \times \frac{1}{2}n(n+1)+1=4n(n+1)+1=4n^2+4n+1=(2n+1)^2$

n is an integer, so 2n+1 is also an integer. 8s+1 is equal to the square of 2n+1, so it's a square number.

2n+1 is an odd integer for any value of n. The square of an odd integer is always an odd integer. Therefore 8s+1=(2n+1)² is odd.

8s+1 is an odd square number.

7 0

3 years ago

Jim decided to go for a drive in his car. He started out at 0 miles per hour (mph). He then

Ghella [55]

20+35-11 - 7 =37 !

i calculated it ;)

6 0

3 years ago

Read 2 more answers

The midpoint of JK is M(4, 5). One endpoint is J(5,2). Find the coordinates of the other endpoint K.

Bogdan [553]

Answer: