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mixas84 [53]
3 years ago
12

At the end of the day, a local bakery sold 83 cakes and had to throw out 7 cakes due to baking errors. Each cake cost the bakery

$6.25 to make. The bakery, in turn, sold each cake for $12.75. What was the total profit earned by the bakery today?
Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

The total profit earned by the bakery today was of $495.75.

Step-by-step explanation:

Spending:

83 + 7 = 90 cakes made, each costing 6.25. So

S = 90*6.25 = 562.5

Earnings:

83 cakes sold by $12.75, so:

E = 83*12.75 = 1058.25

Profit:

Earnings subtracted by spending, so:

P = E - S = 1058.25 - 562.5 = 495.75

The total profit earned by the bakery today was of $495.75.

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3 years ago
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Suppose T is a transformation from ℝ2 to ℝ2. Find the matrix A that induces T if T is reflection over the line y=1/2x
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Answer:

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Step-by-step explanation:

We have to see how the canonical vectors are transformed throught T. Lets first define T in any basis.

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By summing the first vector with the double of the second one we get, using linearity

T(0,5) = T( (2,1) + 2(-1,2)) = T(2,1) + 2T(-1,2) = (2,1) + 2(1,-2) = (4,-3)

Hence, T(0,1) = (4/5,-3/5)

Now, we take the second vector and substract it the double of the first one (to kill the second variable)

T(-3,0) = T( (-1,2) - 2*(2,1) ) = T(-1,2) -2T(2,1) = (1,-2)-2(2,1) = (-3,-4)

Therefore, T(1,0) = (1,4/3)

The matrix A induced by  T has in its first column T(1,0) and in its second column T(0,1). We conclude that

A = \left[\begin{array}{cc}1&\frac{4}{5}\\\frac{4}{3}&-\frac{3}{5}\end{array}\right]

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