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2 years ago

15

HELPS PLS 44 and 17 what is y and x

1 answer:

olga_2 [115]2 years ago

3 0

Y is 11.82
i put my working below

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Can somebody help me with my geometry?

ahrayia [7]

The slope of AC is -0.4

Proof:
In triangles ABC and DBE,
∠DBE is common to both triangles.
AB = 2DB (D is the midpoint of the interval AB)
Also, BC = 2BE (E is the midpoint of the interval BC)

Thus triangles ABC and DBE are similar in the ratio 2:1

Since, they are similar, ∠BDE must equal ∠BAC (corresponding angles in similar triangles)

If ∠BDE = ∠BAC, DE must be parallel to AC (corresponding angles are equal along parallel lines)
Thus, the slope of AC = the slope of DE
Thus, the slope of AC is -0.4

3 0

3 years ago

Average Inventory The Yasuko Okada Fragrance Company (YOFC) receives a shipment of 400 cases of specialty perfume early Monday m

Ksenya-84 [330]

Answer:

Step-by-step explanation:

At the end of any given business day, CFFC has 400-80t cases of perfume on hand, where t = 1 represents Monday, t = 2 represents Tuesday and so on. The inventory becomes nil on Friday evening. So,

The values of a and b are

a = 0

b = 5

Using the formular for average value, we have the average value as

$\frac{1}{5-0}\int\limits^5_0 {(400-80t)}dt\\\\=\frac{1}{5}(400t-\frac{80t^2}{2})\limits^5_0\\\\=\frac{1}{5}(400t-40t^2)\limits^5_0\\\\=\frac{1}{5}(2000-1000)\\\\=200$

Average inventory is 200 cases

8 0

3 years ago

Diego has some money in his bank account before he starts a summer job. He deposits

Leto [7]

Answer:

he earns $7 per hour

Step-by-step explanation:

6 0

2 years ago

Anybody can help on anyone of these please quick !!!

malfutka [58]

19) B
20) D
21) A
22) B
23) C
24) C

8 0

3 years ago

Select all the expressions that are equivalent to (2)^n+³

eimsori [14]

Answer:

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

$a^{m}$ × $a^{m}$ = $a^{m+n}$
$(a^{m})^{n}$ = $a^{m*n}$

Now let us find the equivalent expressions of $(2)^{n+3}$

A.

∵ 4 = 2 × 2

∴ 4 = $2^{2}$

∴ $(4)^{n+2}$ = $(2^{2})^{n+2}$

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴ $(4)^{n+2}$ = $(2)^{2n+4}$

B.

∵ 4 = 2 × 2

∴ 4 = 2²

∴ $4(2)^{n+1}$ = 2² × $(2)^{n+1}$

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴ $4(2)^{n+1}$ = $(2)^{n+3}$

C.

∵ 8 = 2 × 2 × 2

∴ 8 = 2³

∴ $8(2)^{n}$ = 2³ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴ $8(2)^{n}$ = $(2)^{n+3}$

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = $2^{4}$

∴ $16(2)^{n}$ = $2^{4}$ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴ $16(2)^{n}$ = $(2)^{n+4}$

E.

$(2)^{2n+3}$ is in its simplest form

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

3 0

3 years ago