All categories

3 years ago

A small pack of trading cards cost $5, and a large pack costs $10. Eliza wants to spend $30 on trading

Mathematics

2 answers:

Softa [21]3 years ago

4 0

C: 4 small, 1 large. i think you meant to put C for that one but it makes sense because each small costs 5 so if you multiply 5 times 4 you get 20 so you then have 10 dollars left over so you can get one large and that would equal 30. if this helped you please give me brainliest

LekaFEV [45]3 years ago

3 0

Answer:

the answer is 4 small 1 large

You might be interested in

Which expression is equivalent to √4j^4/9k^8?

solmaris [256]

$\frac{ 2j^{2} }{ 3^{4} }$
SQRT each individual bit: 4 and $j^{4}$ and 9 and $k^{8}$

6 0

3 years ago

Read 2 more answers

Two is subtracted from a number, and then the difference is multiplied by 5. The result is 30

Vanyuwa [196]

Answer:

Step-by-step explanation:

8-2=6

6x5=30

6 0

2 years ago

Read 2 more answers

Solve AABC. Round your answers to the nearest hundredth, if necessary

Aloiza [94]

Answer:

$C=25^{\circ},\\a\approx 10.72,\\b\approx 11.83$

Step-by-step explanation:

The sum of the interior angles of a triangle is 180 degrees. Thus, angle C must be $180-90-65=25^{\circ}$ .

In any triangle, the Law of Sines is given by $\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$ .

Therefore, we have:

$\frac{\sin 90^{\circ}}{b}=\frac{\sin 25^{\circ}}{5},\\\\b=\frac{5\sin90^{\circ}}{\sin 25^{\circ}}=11.8310079158\approx \boxed{11.83}$

$\frac{a}{\sin 65^{\circ}}=\frac{5}{\sin25^{\circ}},\\a=\frac{5\sin 65^{\circ}}{\sin25^{\circ}}=10.7225346025\approx \boxed{10.72}$

8 0

3 years ago

Since the slope of a vertical line is undefined, is it possible ofr vertical lines to be parallel?

ikadub [295]

Yes, because if you have x=5 and x=10 they are parallel lines to each other.

6 0

3 years ago

Suppose an airline policy states that all baggage must be box shaped with a sum of length, width, and height not exceeding 174 i

Leya [2.2K]

Answer:

The square-based box with the greatest volume under the condition that the sum of length, width, and heigth does not exceed 174 in is a cube with each edge of 58 in and a volume of $195112 in^{3}$

Step-by-step explanation:

For this problem we have two constraints, that are as follows:

1) Sum of length, width, and heigth not exceeding 174 in

2) Lenght and width have the same measure (square-based box)

We know that volume is equal to the product of all three edges, and with the two conditions into account we have the next function:

$V=(w^{2})(174-2w)\\V=174w^{2}-2w^{3}$

The interval of interest of the objective function is [0, 87]

This problem requieres that we maximize the function that defines the volume. We start calculating the derivative of the function, wich is:

$V'=348w-6w^{2} \\V'=(348-6w)(w)$

We need to remember that the derivative of a function represents the slope of said function at a given point. The maximum value of the function will have a slope equal to zero.

So we find the value in wich the derivative equals zero:

$0=(348-6w)(w)\\w_1=0\\w_2=348/6=58$

The first value ( $w=0$ ) will leave us with a 'height-only box', so the answer must be $w=58 in$

The value is between the interval of interest.

And, once we solve for the constraints, we have that:

Lenght = Width = Heigth = 58 in

Volume = $195112 in^{2}$

8 0

3 years ago