i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Answer:
10) x=9
11) x=25
Step-by-step explanation:
a triangle is 180º total
10) 2x+8x+90=180
10x=90
x=9
11) 3x+1+2x+2+2x+2=180
7x+5=180
7x=175
x=25
Answer:
idk what the improper fraction would be but
8x-24+10-6x=12
2x-14=12
2x=26
x=13
Step-by-step explanation:
2kg=2000g so do 275/2000 and cancel down to 11/80 :)