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Alika [10]
3 years ago
10

Can the sides of a right triangle have sides the lengths of 48.5ft, 32.5ft, and 30 ft?

Mathematics
2 answers:
NeX [460]3 years ago
7 0

Answer:

No, you can't have a right triangle with the sides 48.5ft, 30ft, 32.5ft.

Step-by-step explanation:

48.5 + 30 + 32.5 = 111 ft

Triangle's total sides: 180.

One side has to be equal to 90ft.

maxonik [38]3 years ago
4 0

Answer:

Step-by-step explanation:

32.5²+30²=1056.25+900=1956.25

48.5²=2352.25≠1956.25

so it is not a right angled triangle.

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A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five
exis [7]

Answer:

\dfrac{14}{29}

Step-by-step explanation:

Let <em>P(A) </em>be the probability that goggle of type A is manufactured

<em>P(B) </em>be the probability that goggle of type B is manufactured

<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

<em>P(A)</em> = 30%

<em>P(B)</em> = 70%

<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

P(A \cap E) will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

P(B \cap E) will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

P(E \cap A) = P(A) \times P(E/A)

P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%

P(E \cap B) = P(B) \times P(E/B)

P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%

P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

P(B/E) = \dfrac{P(E \cap B)}{P(E)}

\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}

So, the required probability is \dfrac{14}{29}.

7 0
3 years ago
Help! I’ll give you the best rating
fenix001 [56]
Sandi did not follow PEMDAS. She added before multiplying and dividing. Her answer should be 18 because 6 • 4 = 24, 2 / 2 = 1, 24 + 1 = 25, 25 - 7 = 18
3 0
3 years ago
That is, what is the 142nd odd number?​
Kitty [74]

Answer and step-by-step explanation:

I believe it is 287. I am not entirely sure, but I believe that is the answer.

4 0
2 years ago
A is center of one circle and C is the center of the other circle. Select all line segments that must have the same length as se
Dominik [7]

Based on the circles shown in the diagram attached above, the line segments that must have the same length as segment AB are:

  1. Segment BC.
  2. Segment CD.

<h3>What is a circle?</h3>

A circle can be defined as a closed, two-dimensional curved geometric shape with no edges or corners. Also, a circle refers to the set of all points in a plane that are located at a fixed distance (radius) from a fixed point (central axis).

<h3>The equation of a circle.</h3>

Mathematically, the standard form of the equation of a circle is given by;

(x - h)² + (y - k)² = r²

Where:

  • h and k represents the coordinates at the center.
  • r represents the radius of a circle.

<h3>What is a line segment?</h3>

A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.

Based on the circles shown in the diagram attached above, the line segments that must have the same length as segment AB are:

  1. Segment BC.
  2. Segment CD.

Read more on line segment here: brainly.com/question/18315903

#SPJ1

3 0
1 year ago
The point (-3, 4) is on the line x+4y=13.
lys-0071 [83]

Answer:

yes

Step-by-step explanation:

To determine if the point lies on the line substitute the coordinates into the left side of the equation and if equal to the right side then the point lies on the line

- 3 + (4 × 4) = - 3 + 16 = 13 = right side

Hence (- 3, 4) lies on the line x + 4y = 13

5 0
3 years ago
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