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Stella [2.4K]
3 years ago
6

14. Monique has 15 oranges, 9 peaches, and 18 pears. She wants to put all of the fruit into decorative baskets. Each basket must

have the same number of pieces of fruit in it. Without mixing fruits, what is the greatest number of pieces of fruit that Monique can put in each basket?
Mathematics
1 answer:
Ksivusya [100]3 years ago
3 0

Answer:

3

Step-by-step explanation:

15/3=5

9/3=3

18/3=6

answer is 3 I believe.

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After school Philippe spent 1 3/4 hours at baseball practice, 2 1/4 hours on homework, and 1/4 hour getting ready for bed. About
marshall27 [118]

Answer:

4 hours. 1 3/4 is about 2, and 2 1/4 rounds to 2. 1/4 would round to 0, but it would not affect the estimate's accuracy much because we rounded up by 1/4 on 1 3/4 already. Philipe spent about 4 hours on activities.  

Step-by-step explanation:

4 0
3 years ago
Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

6 0
3 years ago
there is 29cm if green ribbon. a blue ribbon is 9cm shorter than the green ribbon. how long is the blue ribbon ​
a_sh-v [17]

Answer:20cm

Step-by-step explanation:

If the blue ribbon is 9cm shorter you’re just subtracting 29-9 which is 20cm.

8 0
3 years ago
HURRY HELP PLS‼️‼️‼️
Brums [2.3K]

Answer:

Step-by-step explanation:

To solve this problem you need the function

 

h(t) = -16t2 + v0t + h0

where t = time

v0 is the initial velocity, which in our case is 0

h0 = initial height, which in our case is 256

h(t) = 0 since we want to know when the ball will hit the ground.

 

0 = -16 t2 + 256

 

And we can solve for t

 

If we rearrange the terms we see that this is a difference of 2 squares

0 = 256 - 16t2

 

0 = (16-4t)(16+4t)

Setting each factor = 0

16-4t=0       16+4t=4

t = 4             t = -4

 

The second solution is discarded as time cannot be negative.

 

So the ball will hit the ground in 4 seconds.

6 0
3 years ago
Sweets cost 6p how much would 43 sweets cost?
SCORPION-xisa [38]
The answer is 258 pennies
7 0
3 years ago
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