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IgorLugansk [536]
3 years ago
10

If 2 apple and 5 bananas cost 4.20 dollars and 3 apples and 4 bananas coke 4.So dollars what is the price of a apple and banana

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

An apple costs $0.45 and a banana costs $0.66.

Step-by-step explanation:

This question is solved by a system of equations.

I am going to say that:

An apple costs x.

A banana costs y.

2 apple and 5 bananas cost 4.20 dollars

This means that:

2x + 5y = 4.2

So

2x = 4.2 - 5y

x = 2.1 - 2.5y

3 apples and 4 bananas cost 4.

This means that:

3x + 4y = 4

Since x = 2.1 - 2.5y

3(2.1 - 2.5y) + 4y = 4

6.3 - 7.5y + 4y = 4

3.5y = 2.3

y = \frac{2.3}{3.5}

y = 0.66

Then:

x = 2.1 - 2.5(0.66) = 0.45

An apple costs $0.45 and a banana costs $0.66.

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Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

A\cap B={HH}

B\cap C={HH}

A\cap C={HH}

P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

P(A)=\frac{2}{4}=\frac{1}{2}

Number of favorable cases to event B=2

Number of favorable cases to event C=2

P(B)=\frac{2}{4}=\frac{1}{2}

P(C)=\frac{2}{4}=\frac{1}{2}

If the two events A and B are independent then

P(A)\cdot P(B)=P(A\cap B)

P(A\cap)=\frac{1}{4}

P(B\cap C)=\frac{1}{4}

P(A\cap C)=\frac{1}{4}

P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}

P(B)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(B)=P(A\cap B)

Therefore, A and B are independent

P(B)\cdot P(C)=P(B\cap C)

Therefore, B and C are independent

P(A\cap C)=P(A)\cdot P(C)

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

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3 years ago
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