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posledela
3 years ago
15

Pleaseee help answer correctly !!!!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

Mathematics
1 answer:
NemiM [27]3 years ago
4 0

Answer:

4

Step-by-step explanation:

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What is the answer :((
Mazyrski [523]

Answer:

x + 11

Step-by-step explanation:

out you're going from -3 to 8 and that is 11 jumps so if x is -3 then it would be  x + 11

5 0
3 years ago
Whoever answers this correct gets most brainly!!
zzz [600]
D the last please tell me if I’m right thanks
5 0
4 years ago
Brainliest will be given to the correct answer!
IrinaK [193]

Answer:

A) The height of the trapezoid is 6.5 centimeters.

B) We used an algebraic approach to to solve the formula for b_{1}.  b_{1} = \frac{2\cdot A}{h}-b_{2}

C) The length of the other base of the trapezoid is 20 centimeters.

D) We can find their lengths as both have the same length and number of variable is reduced to one, from b_{1} and b_{2} to b. b = \frac{A}{h}

Step-by-step explanation:

A) The formula for the area of a trapezoid is:

A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2}) (Eq. 1)

Where:

h - Height of the trapezoid, measured in centimeters.

b_{1}, b_{2} - Lengths fo the bases, measured in centimeters.

A - Area of the trapezoid, measured in square centimeters.

We proceed to clear the height of the trapezoid:

1) A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2}) Given.

2) A = 2^{-1}\cdot h \cdot (b_{1}+b_{2}) Definition of division.

3) 2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}] Compatibility with multiplication/Commutative and associative properties.

4) h = \frac{2\cdot A}{b_{1}+b_{2}} Existence of multiplicative inverse/Modulative property/Definition of division/Result

If we know that A = 91\,cm^{2}, b_{1} = 16\,cm and b_{2} = 12\,cm, then height of the trapezoid is:

h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}

h = 6.5\,cm

The height of the trapezoid is 6.5 centimeters.

B) We should follow this procedure to solve the formula for b_{1}:

1) A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2}) Given.

2) A = 2^{-1}\cdot h \cdot (b_{1}+b_{2}) Definition of division.

3) 2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2}) Compatibility with multiplication/Commutative and associative properties.

4) 2\cdot A \cdot h^{-1} = b_{1}+b_{2} Existence of multiplicative inverse/Modulative property

5) \frac{2\cdot A}{h} +(-b_{2}) = [b_{2}+(-b_{2})] +b_{1} Definition of division/Compatibility with addition/Commutative and associative properties

6) b_{1} = \frac{2\cdot A}{h}-b_{2} Existence of additive inverse/Definition of subtraction/Modulative property/Result.

We used an algebraic approach to to solve the formula for b_{1}.

C) We can use the result found in B) to determine the length of the remaining base of the trapezoid: (A= 215\,cm^{2}, h = 8.6\,cm and b_{2} = 30\,cm)

b_{1} = \frac{2\cdot (215\,cm^{2})}{8.6\,cm} - 30\,cm

b_{1} = 20\,cm

The length of the other base of the trapezoid is 20 centimeters.

D) Yes, we can find their lengths as both have the same length and number of variable is reduced to one, from b_{1} and b_{2} to b. Now we present the procedure to clear b below:

1) A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2}) Given.

2) b_{1} = b_{2} Given.

3) A = \frac{1}{2}\cdot h \cdot (2\cdot b) 2) in 1)

4) A = 2^{-1}\cdot h\cdot (2\cdot b) Definition of division.

5) A\cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot b Commutative and associative properties/Compatibility with multiplication.

6) b = A \cdot h^{-1} Existence of multiplicative inverse/Modulative property.

7) b = \frac{A}{h} Definition of division/Result.

8 0
4 years ago
A 14-foot tree casts an 18-foot shadow. Find the angle of elevation from the tip of the shadow to the top of the tree. Round the
serious [3.7K]
The tangent of the angle would be given by 14/18, so the angle would be:
tan⁻¹(14/18)
= 37.9 to the nearest tenth of a degree
6 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
Ostrovityanka [42]
Y = 3x - 1
-------------
5 0
3 years ago
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