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Scorpion4ik [409]
2 years ago
9

In triangle ABC, AB = 11 cm, BC = 9 cm and CA = 10 cm. Find the area of triangle ABC.

Mathematics
1 answer:
max2010maxim [7]2 years ago
7 0

Answer:

Area = 42.43 square cm

Step-by-step explanation:

Using Heron's Formula :

 Area = \sqrt{s\times (s-a) \times (s-b) \times(s -c)} \ , \ where  \ s \ =\ \frac{a+ b+ c}{2}

<em><u>Find Area :</u></em>

<em><u></u></em>

s = \frac{11 + 9 + 10 }{2} = \frac{30}{2} = 15

Area = \sqrt{15 \times ( 15 - 11 ) \times { (15 - 9 ) \times ( 15 -10)}\\\\

      = \sqrt{15 \times 4 \times 6 \times 5}\\\\=\sqrt{1800}

      = 42 . 43 \ cm^2

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Answer:

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Step-by-step explanation:

The trick is that we need to set up two equations. Nor simplicity's sake I'm going to say the first number is x and the second number is y.

First we know that the first number (x) is 4 less than the second number (y).

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Then we know that 4 times x is 14 more than 5 times the second. More is addition and times is multiplication.

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Now we use substitution to find out what x (the first number) is, subbing x-4 in for y.

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