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Mariulka [41]
2 years ago
10

How can we find the number of moles in equilibrium?

Chemistry
1 answer:
pychu [463]2 years ago
5 0
<span>You can find the number of moles in equilibrium if you got the chemical reaction correctly. Make sure that you got the exact chemical formula of the substance that is reacting and the yielded product. If you got them, balance the chemical reaction. If the chemical reaction is balanced, the system is in equilibrium. You can find the number of moles in equilibrium at the coefficients of the chemical substances you are balancing. For example, N2 + 3H2 -> 2NH3. The number of moles of N2 is 1, H2 is 3 and NH3 is 2.</span>
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Physical and chemical changes are similar because they are both caused by the interaction of two or more particles.

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7 0
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3 years ago
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1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

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• using the molar mass of Ca(OH)2 (74g/mol).

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• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

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• using the molar mass of HNO3 (63.02g/mol).

4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

So, 7.32g of HNO3 are required.

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