To find the density of racon all you have to do is to divide number of racoons with surface area because as name says you need to get x number of racoons per m^2
its own name tells you what you need to divide with what.
answer is:
20/10 = 2 raccoons per m^2
Answer:
x-2
Step-by-step explanation:
(7x^2-14x)/7x
Distribute the 7
x-2
Answer:
see explanation
Step-by-step explanation:
f(x) × g(x)
= 11(123x - 40) ← distribute
= 1353x - 440
Substitute x = - 4 into the product
= (1353 × - 4) - 440
= - 5412 - 440
= - 5852
Answer:
x = 23
y = 7
z = 11
Step-by-step explanation:
Since ∆PRS ≅ ∆CFH, therefore,
m<R = m<F
13y - 1 = 90° (substitution)
Add 1 to both sides
13y - 1 + 1 = 90 + 1
13y = 91
Divide both sides by 13
13y/13 = 91/13
y = 7
Since ∆PRS ≅ ∆CFH, therefore,
PS = CH
2x - 7 = 39 (substitution)
Add 7 to both sides
2x - 7 + 7 = 39 + 7
2x = 46
Divide both sides by 2
2x/2 = 46/2
x = 23
Since ∆PRS ≅ ∆CFH, therefore,
m<S = m<H
Find m<S
m<S = 180 - (m<P + m<R) (sum of ∆)
m<S = 180 - (28 + (13y - 1)) (substitution)
Plug in the value of y
m<S = 180 - (28 + (13)(7) - 1))
m<S = 180 - (28 + 91 - 1)
m<S = 180 - 118
m<S = 62°
Therefore, since m<S = m<H,
62° = 6z - 4 (substitution)
Add 4 to both sides
62 + 4 = 6z - 4 + 4
66 = 6z
Divide both sides by 6
66/6 = 6z/6
11 = z
