Answer:
Infinitely many solutions
Step-by-step explanation:
Since y=-3x-2, plug it in (2)
6x+2(-3x-2)=-4.
Distribute:
6x-6x-4=-4
-4=-4
Infinetly many solutions.
Hope this helps :)
Answer: no
Step-by-step explanation: to change a fraction back to a improper fraction
multiply the whole number by the denominator and then add it to the numerator but be careful with negative. You can check this process by changing the improper fraction back to proper. If i change -17/10 i get -1 7/10. the correct answer is -23/10.
Answer:
Step-by-step explanation:
hello :
z⁴=1+i given : z² = t t is the complex number so : z⁴= (z²)² =t²
solve for t this equation : t² = 1+i
if : t = x+iy t² =(x+iy)² = x²+2xiy+(iy)² =x²-y²+2xyi ...... ( i² = -1)
t² = 1+i means : x²-y²+2xyi = 1+i
you have this system : x²-y² = 1.....(*)
2xy = 1.....(**)
slve for x and y you ca add this equation : ....(***)
( use : t² = 1+i
/t²/ = /1+i/ so :/t/² = /1+i/ .... (√(x²+y²))²=√(1²+1²) =√2 means x²+y² = √2)
the system is : x²-y² = 1.....(*)
2xy = 1.....(**)
x²+y² = √2 ....(***)
add (*) and (***) : 2x²= 1+√2
x² = (√2+1)/2
substrac (*) and (***) you have : y² = (√2-1)/2
use (**) the proudect xy is positif (same sign) so :
x=√( (√2+1)/2) and y = √( (√2-1)/2) so : t1 =√( (√2+1)/2)+i√( (√2-1)/2)
x= -√( (√2+1)/2) and y = -√( (√2-1)/2) so :t2= -t1
same method for equation : z² =t1 ..(2 solution ) and z² = t2..(2 solution )
1. It is the product of a square, meaning it can be simplified to (x+10)(x+10) or (x+10)^2
