Composed of molecules formed by atoms of two or more different elements.
Particles of the substance have the most kinetic energy when the substance is(a)1. A gas. The part of the graph that represents where the substance has the least amount of potential energy is labeled(b)1. Solid.
Gas molecules have the highest average velocities among the three states of matter so gas has the highest kinetic energy. During freezing, a substance loses a lot of potential energy so solid has the least potential energy.
D.because the water is needed to wet the sand and keep the reaction safe
The question is missing the number of moles of carbon dioxide that will react with water.
I will work the problem with an arbitrary amount of carbon dioxide to show how to solve it.
For this, I will take 2.40 moles of carbon dioxide.
Answer:
- <u>The number of moles of oxygen atoms produced is equal to the number of moles of carbon dioixide that react: 2.40 moles of oxygen.</u>
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- 2.40 has 3 significant figures.
Explanation:
<u>1) Word equation:</u>
- carbon dioxide gas + liquid water (in the presence of light) → aqueous glucose + oxygen gas
<u>2) Balanced chemical equation</u>
- 6CO₂ (g) + 6H₂O (l) → C₆H₁₂O₆ (aq) + 6O₂(g)
<u>3) Mole ratios</u>
- 6 mol CO₂ (g) : 6 mol H₂O (l) : 1 mol C₆H₁₂O₆ (aq) : 6 mol O₂(g)
<u>4) Set a proportion:</u>
It is assumed that there is plenty liquid water (excess reactant), so you can set a proportion with the number of moles of carbon dioxide:
- 6 mol CO₂ / 6 mol O₂ = 2.40 mol CO₂ / x
From which, x = 2.40 mol O₂
So, the number of moles of oxygen produced is equal to the number of moles of carbon dioxide that react.
Since the number of moles of reactant has 3 significant figures, and the stoichiometric coefficients are considered exact, the answer also has 3 significant figures.
Answer:
2.95 g of CH₄
Explanation:
To start this, we determine the equation:
4H₂ + CO₂ → CH₄ + 2H₂O
4 moles of hydrogen react to 1 mol of carbon dioxide in order to produce 1 mol of methane and 2 moles of water.
To determine the limiting reactant, we need to know the moles of each reactant.
8.1 g . 1 mol/ 44g = 0.184 moles of carbon dioxide
2.3 g . 1mol / 2g = 1.15 moles of hydrogen
4 moles of hydrogen react to 1 mol of CO₂
Then, 1.15 moles may react to (1.15 . 1) /4 = 0.2875 moles
We only have 0.184 moles of CO₂, so this is the limiting reactant. Not enough CO₂ to complete the 0.2875 moles that are needed.
Ratio is 1:1. 1 mol of CO₂ produces 1 mol of methane
Then, 0.184 moles of CO₂ will produce 0.184 moles of CH₄
We convert moles to mass: 0.184 mol . 16 g /mol = 2.95 g