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3 years ago

PLEASE HELP!

Mathematics

1 answer:

MakcuM [25]3 years ago

3 0

Step-by-step explanation:

-12 = a(0+2)²-20

-12=4a -20

4a = 20-12

4a=8

a=2

y = 2x²+ 8x -12

=> y = 2 x² + 8 x + -12

2 , 8 , -12

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Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

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Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
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$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
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$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
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I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
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Hope this helps!

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