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andrew11 [14]
3 years ago
13

To the nearest 0.1 ounce, a package of oatmeal weighs 13.0 ounces. What is the LEAST amount the package can actually weigh?

Mathematics
1 answer:
Paha777 [63]3 years ago
5 0
To the nearest 0.1 ounce, a package of oatmeal
weighs 13.0 ounces. What is the LEAST amount
the package can actually weigh?
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A stadium has a seating capacity of 65,000 spectators.
Montano1993 [528]
X = capacity

64999 < x <  \ 65001
3 0
3 years ago
3^2 ÷ 3^-1 explain the steps
Ksenya-84 [330]
First you would need to Simplify <span>{3}^{2}<span>3<span>​2​​</span></span></span> to <span>99

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then you would need to use a ÷ b/c = a * c/b and get 9*3

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7 0
3 years ago
How to find the area of a sector with a sector angle of 72 degrees and a radius of 14 cm​
skad [1K]

Answer:

Exact area: 39.2π cm²

Approximate area: 123.2 cm²

Step-by-step explanation:

The area of a circle is πr².

A full circle can be thought of as a sector of a circle with 360° of central angle. For a sector of a circle with a central angle of n°, multiply the area of the circle by the fraction n°/360°.

The formula for the area of a sector of circle with central angle n° and radius r is

A = (n°)/(360°) × πr²

Here we have n = 72; r = 14 cm

A = (n°)/(360°) × πr²

A = (72°)/(360°) × π × (14 cm)²

A = 39.2π cm² = 123.2 cm²

7 0
1 year ago
Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A samp
shutvik [7]

Answer:

0.9910 = 99.10% probability that a sample of 170 steady smokers spend between $19 and $21

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20, standard deviation of 5:

This means that \mu = 20, \sigma = 5

Sample of 170:

This means that n = 170, s = \frac{5}{\sqrt{170}}

What is the probability that a sample of 170 steady smokers spend between $19 and $21?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{5}{\sqrt{170}}}

Z = 2.61

Z = 2.61 has a p-value of 0.9955

X = 19

Z = \frac{X - \mu}{s}

Z = \frac{19 - 20}{\frac{5}{\sqrt{170}}}

Z = -2.61

Z = -2.61 has a p-value of 0.0045

0.9955 - 0.0045 = 0.9910

0.9910 = 99.10% probability that a sample of 170 steady smokers spend between $19 and $21

3 0
3 years ago
PLEASE HELP ILL MARK BRAINEST!!!!
earnstyle [38]

Answer:

(-3,8) would NOT fit the table.

6 0
3 years ago
Read 2 more answers
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