Answer:
The answer to your question is 1) 1336 g of Fe₂O₃ 2) 1 mol of H₃PO₄
Explanation:
1)
Data
mass of Fe₂O₃ = ?
moles of Fe = 16.7
Balanced chemical reaction
4Fe + 3O₂ ⇒ 2Fe₂O₃
a.- Calculate the moles of Fe₂O₃
4 moles of Fe ----------------- 2 moles of Fe₂O₃
16.7 moles of Fe -------------- x
x = (16.7 x 2)/4
x = 33.4/4
x = 8.35 moles of Fe₂O₃
b.- Calculate the molar mass of Fe₂O₃
Fe₂O₃ = (2 x 56)+ (3 x 16) = 112 + 48 = 160 g
c.- Convert moles to mass
160 g of Fe₂O₃ ------------ 1 mol
x ------------ 8.35 moles of Fe₂O₃
x = (8.35 x 160)/1
x = 1336 g of Fe₂O₃
2)
moles of H₃PO₄ = ?
mass of P₄O₁₀ = 71 g
Balanced chemical reaction
P₄O₁₀ + 6H₂O ⇒ 4H₃PO₄
a.- Calculate the molar mass of P₄O₁₀
P₄O₁₀ = (31 x 4) + (16 x 10) = 124 + 160 = 284 g
b.- Convert the mass of P₄O₁₀ to moles
284 g ------------------- 1 mol
71 g -------------------- x
x = (71 x 1)/284
x = 0.25 moles of P₄O₁₀
c.- Calculate the moles of H₃PO₄
1 mol of P₄O₁₀ ---------------- 4 moles of H₃PO₄
0.25 moles ----------------- x
x = (0.25 x 4) / 1
x = 1 mol of H₃PO₄
