Answer:
1. Covalent Bond
2. Ionic Bond
Explanation:
Covalent bonds are defined as the bond in which sharing of electrons takes place between atoms. The sharing of electrons is in equal number so that it form a stable balance of attraction and repulsion between atoms. In the given example of CO2 (first image) oxygen is sharing equal number of electrons with carbon to form a stable bond called covalent bond.
Ionic bonds are formed when valence electrons are transferred to other atoms and form oppositely charged ions. In ionic bond formation, the atoms that gain electrons become negatively charged and the atoms that loses electrons become positively charged. In the given example of Ca Cl2, Ca is also giving its 2 valence electrons to each Cl and there is no stable balance of attraction and repulsion between atoms.
Hence, the correct answer is:
1. Covalent Bond
2. Ionic Bond
I don’t have a picture but I can describe it to you.
The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.
The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.
Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.
Hope this helps!
Hydrogen bonds are strong intermolecular forces created when a hydrogen atom bonded to an electronegative atom approaches a nearby electronegative atom. Greater electronegativity of the hydrogen bond acceptor will lead to an increase in hydrogen-bond strength.
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The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles
<h3>How to determine the mole of NH₃ produced </h3>
- Mass of NH₃ = 150 g
- Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
Mole = mass /molar mass
Mole of NH₃ = 150 / 17
Mole of NH₃ = 8.82 moles
<h3>How to determine the mole of N₂ needed </h3>
Balanced equation
N₂ + 3H₂ —> 2NH₃
From the balanced equation above,
2 moles of NH₃ were produced by 1 mole of N₂.
Therefore,
8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.
Thus, 4.41 moles of N₂ is needed for the reaction.
Learn more about stoichiometry:
brainly.com/question/14735801
Please provide the hydrate
