3 years ago

R1 - Writing and using formulae

Mathematics

1 answer:

svetlana [45]3 years ago

8 0

Answer:

im trying to do a challenge because this kid deleted all my answers

Step-by-step explanation:

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A number added to one third of itself equals 12 . what is the number

Drupady [299]

Answer:

Step-by-step explanation:

x+1/3x=12

(3x+1x)/3=12

4x/3=12

4x=12×3

4x=36

x=36/4

x=9

8 0

3 years ago

Read 2 more answers

What I use the Pythagorean theorem for this problem?

andrew-mc [135]

No you would not use the Pythagorean Theorem, You would take the two sides and multiply them together, and divide it by 2.

8 0

3 years ago

Round 2.12747677748 to the nearest ten-thousandth.

cupoosta [38]

Answer:

Step-by-step explanation:

7 0

3 years ago

A photo is 15 cm high and 9 cm wide Michael wants to but porcelain shrink it so it's height is 6 cm High how wide will it then b

weqwewe [10]

Answer:

3.6cm

Step-by-step explanation:

Given data

We are given that the dimension of the photo is

Height= 15cm

Width= 9cm

That is

15cm height will make 9cm width

hence 6cm height will make x widht

cross multiply

9*6= 15*x

54= 15x

x= 54/15

x= 3.6cm

Hence the width will be 3.6cm

3 0

3 years ago

(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.

Andreyy89

$\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1$

Recall that

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

Your sums start at $i=3$ , so in order to apply these formulas directly, you need to compensate for the missing first two terms:

$\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8$

$\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52$

$\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}$

4 0

3 years ago