ABCD is a trapezium AD and BC are parallel
2 answers:
Part (a)
<h3>Answer: 12.1</h3>-----------------------
Work Shown:
We'll apply the sine rule since we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.
Focus on triangle ABD
sin(angle) = opposite/hypotenuse
sin(D) = AB/BD
sin(56) = 10/x
x*sin(56) = 10
x = 10/sin(56)
x = 12.062179
x = 12.1
Make sure your calculator is in degree mode.
===================================================
Part (b)
<h3>Answer: 15.1</h3>-----------------------
Work Shown:
Draw an xy coordinate grid.
Place point A at the origin (0,0).
Point B is 10 units above this, so B is at (0,10).
Point C is at (18,10) since we move 18 units to the right of B.
Point D is at approximately (6.745085, 0). The 6.745085 is from solving tan(56) = 10/x for x.
Refer to the diagram below.
Apply the distance formula for the points C and D.
Segment CD is roughly 15.1 cm long.
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Answer:
P(heads appears on only the last toss) =
Step-by-step explanation:
A fair coin is tossed 3 times in a row.
When a coin is tossed we get a tail or head T or H
The possible outcomes of 3 coins are
T T T , H H H , T H H, H T H, H H T, H T T , T H T, T T H
So total of 8 possible outcomes
heads appears on only the last toss , first and second toss should be tail
So its T T H. Only one possibility
Probability(any event) = number of outcomes / total outcomes
P(heads appears on only the last toss) =
Answer:
x = 0; y = -6; z = 1
Step-by-step explanation:
You want to find the solution to the system of equations ...
- 9x+y-3z=-9
- 10x-y+2z=8
- -10x-y+4z=10
This set of equations is conveniently solved using the matrix row-reduction features of a scientific or graphing calculator, spreadsheet, or any of a number of apps or on-line calculators.
The attachment shows the solution to be ...
(x, y, z) = (0, -6, 1)
__
<em>Additional comment</em>
Solving a system of three or more equations "by hand" often can be done by an ad hoc process. It can be done in systematic fashion using Gauss-Jordan reduction techniques, but that often gets messy. Similarly, Cramer's Rule can be used, but that math tends to involve more arithmetic operations than are really necessary.
Adding the first equation to the other two eliminates the y-variable and reduces the system to two equations in two unknowns.
(9x +y -3z) +(10x -y +2z) = (-9) +(8) . . . . adding [1] and [2]
19x -z = -1 . . . . simplified
(9x +y -3z) +(-10x -y +4z) = (-9) +(10) . . . . adding [1] and [3]
-x +z = 1 . . . . simplified
At this point, we could graph the two equations, or we can proceed algebraically.
Adding these two equations gives ...
(19x -z) +(-x +z) = (-1) +(1)
18x = 0 ⇒ x = 0
Using the second of the reduced equations, we find ...
-x +z = 1
0 +z = 1 ⇒ z = 1
And using the second of the original equations, gives us ...
10(0) -y +2(1) = 8
-y = 6 . . . . . subtract 2
y = -6 . . . . multiply by -1
Then the solution is (x, y, z) = (0, -6, 1), as above.
Answer:
c
Step-by-step explanation:
A perfect square trinomial is always in the form
(a+b)(a+b)=
ie. (x+4)(x+4)=