All categories

2 years ago

Amanda is making cookies and only needs 3/5 of the 10 ounce bag of peanut butter

Mathematics

1 answer:

GaryK [48]2 years ago

5 0

Answer:

She needs 6 ounces of peanut butter chips.

hope this helped :-)

Step-by-step explanation:

10:5=2

1/5 = 2

1/5+1/5+1/5=

2+2+2=

2*3=6

You might be interested in

What are the coordinates of the vertices of ABC? Use the coordinates to find the lengths of ab and . bc

Digiron [165]

The triangle shown is a Pythagorean triple with lengths of 3-4-5.
AC = 3
AB = 4
BC = 5

5 0

3 years ago

Read 2 more answers

Basic functions sample work! Help please

frosja888 [35]

Answer:

See the attachment.

Step-by-step explanation:

Function notation: This means the description of the curve is written in the form ...

f(x) = <an expression that describes the curve in terms of independent variable x>

The name of the function does not have to be "f", though f, g, h are traditional for generic functions. In specific cases, the function name might be related to the value the function delivers: <em>cost(n)</em> might be the function that tells you the cost of producing n items, for example.

The functions shown (square root, reciprocal) should be shapes you have memorized. You can check the scale factor at specific values you know, for example, √4 = 2, or 1/1 = 1. Hence both functions have a scale factor of 1 (no scaling).

___

The domain is the horizontal region where the function is defined. Square root is not defined for negative numbers; reciprocal is not defined for 0. Hence the descriptions of the respective domains must exclude these values.

___

The range is the vertical extent of the values each function produces. The domain and range are the same for both functions shown here.

___

Asymptotes are lines the function approaches but does not reach. The square root function has no such lines. (It reaches vertical at x=0.)

The reciprocal function has a vertical asymptote as x=0 (the value of x that makes the function denominator zero). And, it has a horizontal asymptote at y=0, a value that can be approached, but not reached, as x gets large in either the positive or negative directions.

___

End behavior: The square root function heads off toward (∞, ∞). The reciprocal function heads toward the value defined by the horizontal asymptote: y=0 as x gets large in magnitude.

3 0

2 years ago

Help ASAP!! I have to turn this in soon

ivanzaharov [21]

I believe AFE is 0°
CFE is 105°
And BFD is 90° I think

7 0

2 years ago

Read 2 more answers

F(x) = (128/127)(1/2)x, x = 1,2,3,...7. determine the requested values: round your answers to three decimal places (e.g. 98.765)

Marrrta [24]

A.
$\mathbb P(X\le 1)=\mathbb P(X=1)=\dfrac{128}{127}\left(\dfrac12\right)^1=\dfrac{64}{127}$

b.
$\mathbb P(X>1)=1-\mathbb P(X\le1)=1-\dfrac{64}{127}=\dfrac{63}{127}$

c.
$\mathbb E(X)=\displaystyle\sum_{x=1}^7 x\,f_X(x)=\frac{64}{127}\sum_{x=1}^7 x\left(\frac12\right)^{x-1}$

Suppose $f(y)=\displaystyle\sum_{x=0}^7 y^x$ . Then $f'(y)=\displaystyle\sum_{x=1}^7 xy^{x-1}$ . So if we can find a closed form for $f(y)$ , in terms of $y$ , we can find $\mathbb E(X)$ by evaluating the derivative of $f(y)$ at $y=\dfrac12$ .

$f(y)=\displaystyle\sum_{x=0}^7 y^x=y^0+y^1+y^2+\cdots+y^6+y^7$
$y\,f(y)=y^1+y^2+y^3+\cdots+y^7+y^8$
$f(y)-y\,f(y)=y^0-y^8$
$(1-y)f(y)=1-y^8$
$f(y)=\dfrac{1-y^8}{1-y}$
$\implies f'(y)=\dfrac{7y^8-8y^7+1}{(1-y)^2}$
$\implies\mathbb E(X)=\dfrac{64}{127}f'\left(\dfrac12\right)=\dfrac{64}{127}\times\dfrac{247}{64}=\dfrac{247}{127}$

d.
$\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$

We find $\mathbb E(X^2)$ in a similar manner as in (c).

$\mathbb E(X^2)=\displaystyle\sum_{x=1}^7 x^2\,f_X(x)=\frac{32}{127}\sum_{x=1}^7x^2\left(\frac12\right)^{x-2}$

Now,

$f(y)=\displaystyle\sum_{x=0}^7y^x$
$\implies f'(y)=\displaystyle\sum_{x=1}^7xy^{x-1}$
$\implies f''(y)=\displaystyle\sum_{x=2}^7x(x-1)y^{x-2}$

We know that

$f''(y)=-\dfrac{42y^8-96y^7+56y^6-2}{(1-y)^3}$
$\implies f''\left(\dfrac12\right)=\dfrac{219}{16}$

We also have

$f''(y)=\displaystyle\sum_{x=2}^7x(x-1)y^{x-2}$
$f''(y)=\displaystyle\sum_{x=2}^7x^2y^{x-2}-\sum_{x=2}^7xy^{x-2}$
$f''(y)=\displaystyle\frac1{y^2}\left(\sum_{x=2}^7x^2y^x-\sum_{x=2}^7xy^x\right)$
$f''(y)=\displaystyle\frac1{y^2}\left(\bigg(\sum_{x=1}^7x^2y^x-y\bigg)-\bigg(\sum_{x=1}^7xy^x-y\bigg)\right)$
$f''(y)=\displaystyle\frac1{y^2}\left(\sum_{x=1}^7x^2y^x-\sum_{x=1}^7xy^x\right)$

so that when $y=\dfrac12$ , we get

$\dfrac{219}{16}=4\left(\dfrac{127}{128}\mathbb E(X^2)-\dfrac{127}{128}\mathbb E(X)\right)\implies\mathbb E(X^2)=\dfrac{685}{127}$

Then

$\mathbb V(X)=\dfrac{685}{127}-\left(\dfrac{247}{127}\right)^2=\dfrac{25,986}{16,129}$

6 0

3 years ago

A comic book cost 3.99 it is marked up to 45% what is the final prices of the comic book after it is marked up ?

wolverine [178]

Answer:

Your answer will be C. $5.79.

Step-by-step explanation:

To get this answer, you have to take the original price (3.99) and multiply it by the mark up (45%)

3.99x0.45=1.79

Then, you add 3.99 and 1.79 to get your final answer.

3.99 + 1.79 = 5.78

The answer is off by one penny, BUT, it's tricky to get it exact when you're working with decimals and percentages.

8 0

3 years ago