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Leto [7]
3 years ago
6

Does anyone know this?

Physics
1 answer:
Radda [10]3 years ago
8 0

Answer:

999990900

Explanation:

lololo

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Walking across a carpet can build up a charge due to friction
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Why do electrical devices have resistance​
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As electrons move through the conductor, some collide with atoms, other electrons, or impurities in the metal.
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If 5 mm of rain falls in a 100 m2 field, what volume of rain, in m3, fell in the field?
Nina [5.8K]

The volume of rain that fells in the field is simply given by the area of the field, which is

A=100 mm^2

multiplied by the height of rain that fell, which is

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7 0
4 years ago
Chapter 38, Problem 001
Norma-Jean [14]

Answer:

a) \lambda=2.95x10^{-6}m

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

E=hf

Where h is the Planck's Constant. By the other hand the know that c=f\lambda and if we solve for f we have:

f=\frac{c}{\lambda}

If we replace the last equation into the E formula we got:

E=h\frac{c}{\lambda}

And if we solve for \lambda we got:

\lambda =\frac{hc}{E}

Using the value of the constant h=4.136x10^{-15} eVs we have this:

\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m

\lambda=2.95x10^{-6}m

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of 10^{-6}m

4 0
3 years ago
Some car manufacturers claim that their vehicles could climb a slope of 42 ∘. For this to be possible, what must be the minimum
Paladinen [302]

Answer:

D. 0.9

Explanation:

Calculating minimum coefficient of static friction, we first resolve the forces (normal and frictional) acting on the vehicle at an angle to the horizontal into their x and y components. After this, we can now substitute the values of x and y components into equation of static friction. Diagrammatic illustration is attached.

Resolving into x component:

                        ∑F_{x} = F_{s} - mgsin\alpha =0

                          F_{s} = mgsin\alpha     ------(1)

Resolving into y component:

                        ∑F_{y} = F_{n} - mgcos\alpha =0

                          F_{n} = mgcos\alpha      ------(2)

Static frictional force, F_{s} \leq μ F_{n}       ------(3)

substituting F_{s} from equation (1) and F_{n} from equation (2) into equation (3)

                         mgsin\alpha \leq μ mgcos\alpha

                         sin\alpha \leq μ cos\alpha

                         μ \geq \frac {sin\alpha}{cos\alpha}

                         μ \geq tan\alpha

The angle the vehicles make with the horizontal α = 42°

                         μ ≥ tan 42°

                         μ ≥ 0.9

6 0
3 years ago
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